Chapter 14, Problem 14.28P

Interpretation Introduction

Interpretation:

${\text{E}}^{\text{o}}$ value and equilibrium constant for the reaction has to be calculated.

Base dissociation constant:

The value of ${\text{E}}^{\text{o}}$ can be calculated as,

${\text{E}}^{\text{o}}\text{=}\frac{{\text{-ΔG}}^{\text{o}}}{\text{nF}}$

Where

${\text{E}}^{\text{o}}$ = The standard reduction potential

n = number of electrons

The equilibrium constant for the reaction can be calculated as,

Finding $\text{K}$ from ${\text{E}}^{\text{o}}$

$\text{K}\text{=}\frac{{\text{10}}^{{\text{nE}}^{\text{o}}}}{\text{0}\text{.05916}}\text{at}{\text{25}}^{\text{o}}\text{C}$

Where $\text{K}$ is equilibrium constant