(a) Interpretation: Assuming the solution containing the 5 μ moles of pyruvate dehydrogenase complex and 5 μ moles of all the enzymes of citric acid cycle but none of the metabolic intermediates. This will generate 5 μ moles of CO 2 and then reaction stops. The reason for production more CO 2 after addition of alcohol dehydrogenase and acetaldehyde should be explained. Concept introduction: Pyruvate produced in glycolysis of glucose is oxidised to carbon dioxide and water through a sequence of complicated reaction cycle, popularly named as Krebs cycle. Citric acid and some other tricarboxylic acids occur in the intermediate steps of this reaction sequence, hence the name citric acid cycle and tricarboxylic acid cycle are also given. It is through this cycle of reactions that all food stuff and nutrients are completely oxidised in the cell. All food stuff including carbohydrate must be converted to pyruvate or some other intermediate products for theiroxidation to carbon dioxide and water. Pictorial representation: The citric acid cycle with all the reagent and enzymes and metabolic enzymes can be shown as follows: Figure: Citric acid cycle

Question

Want to see the full answer?

Answer 1

Question

Chapter 13, Problem 7P

Interpretation Introduction

(a) Interpretation:

Assuming the solution containing the 5 μ moles of pyruvate dehydrogenase complex and 5 μ moles of all the enzymes of citric acid cycle but none of the metabolic intermediates. This will generate 5 μ moles of CO₂ and then reaction stops. The reason for production more CO₂ after addition of alcohol dehydrogenase and acetaldehyde should be explained.

Concept introduction:

Pyruvate produced in glycolysis of glucose is oxidised to carbon dioxide and water through a sequence of complicated reaction cycle, popularly named as Krebs cycle. Citric acid and some other tricarboxylic acids occur in the intermediate steps of this reaction sequence, hence the name citric acid cycle and tricarboxylic acid cycle are also given. It is through this cycle of reactions that all food stuff and nutrients are completely oxidised in the cell. All food stuff including carbohydrate must be converted to pyruvate or some other intermediate products for theiroxidation to carbon dioxide and water.

Pictorial representation:

The citric acid cycle with all the reagent and enzymes and metabolic enzymes can be shown as follows:

Figure: Citric acid cycle

Interpretation Introduction

(b) Interpretation:

The μ moles of acetaldehyde required to allow complete oxidation of the pyruvate to 15 μ moles of CO₂ should be calculated.

Concept introduction:

Pyruvate produced in glycolysis of glucose is oxidised to carbon dioxide and water through a sequence of complicated reaction cycle, popularly named as Krebs cycle. Citric acid and some other tricarboxylic acids occur in the intermediate steps of this reaction sequence; hence the name citric acid cycle and tricarboxylic acid cycle are also given. It is through this cycle of reactions that all food stuff and nutrients are completely oxidised in the cell. All food stuff including carbohydrate must be converted to pyruvate or some other intermediate products for theiroxidation to carbon dioxide and water.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 2

Question

Chapter 13, Problem 7P

Interpretation Introduction

(a) Interpretation:

Assuming the solution containing the 5 μ moles of pyruvate dehydrogenase complex and 5 μ moles of all the enzymes of citric acid cycle but none of the metabolic intermediates. This will generate 5 μ moles of CO₂ and then reaction stops. The reason for production more CO₂ after addition of alcohol dehydrogenase and acetaldehyde should be explained.

Concept introduction:

Pyruvate produced in glycolysis of glucose is oxidised to carbon dioxide and water through a sequence of complicated reaction cycle, popularly named as Krebs cycle. Citric acid and some other tricarboxylic acids occur in the intermediate steps of this reaction sequence, hence the name citric acid cycle and tricarboxylic acid cycle are also given. It is through this cycle of reactions that all food stuff and nutrients are completely oxidised in the cell. All food stuff including carbohydrate must be converted to pyruvate or some other intermediate products for theiroxidation to carbon dioxide and water.

Pictorial representation:

The citric acid cycle with all the reagent and enzymes and metabolic enzymes can be shown as follows:

Figure: Citric acid cycle

Interpretation Introduction

(b) Interpretation:

The μ moles of acetaldehyde required to allow complete oxidation of the pyruvate to 15 μ moles of CO₂ should be calculated.

Concept introduction:

Pyruvate produced in glycolysis of glucose is oxidised to carbon dioxide and water through a sequence of complicated reaction cycle, popularly named as Krebs cycle. Citric acid and some other tricarboxylic acids occur in the intermediate steps of this reaction sequence; hence the name citric acid cycle and tricarboxylic acid cycle are also given. It is through this cycle of reactions that all food stuff and nutrients are completely oxidised in the cell. All food stuff including carbohydrate must be converted to pyruvate or some other intermediate products for theiroxidation to carbon dioxide and water.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 3

Question

Chapter 13, Problem 7P

Interpretation Introduction

(a) Interpretation:

Assuming the solution containing the 5 μ moles of pyruvate dehydrogenase complex and 5 μ moles of all the enzymes of citric acid cycle but none of the metabolic intermediates. This will generate 5 μ moles of CO₂ and then reaction stops. The reason for production more CO₂ after addition of alcohol dehydrogenase and acetaldehyde should be explained.

Concept introduction:

Pyruvate produced in glycolysis of glucose is oxidised to carbon dioxide and water through a sequence of complicated reaction cycle, popularly named as Krebs cycle. Citric acid and some other tricarboxylic acids occur in the intermediate steps of this reaction sequence, hence the name citric acid cycle and tricarboxylic acid cycle are also given. It is through this cycle of reactions that all food stuff and nutrients are completely oxidised in the cell. All food stuff including carbohydrate must be converted to pyruvate or some other intermediate products for theiroxidation to carbon dioxide and water.

Pictorial representation:

The citric acid cycle with all the reagent and enzymes and metabolic enzymes can be shown as follows:

Figure: Citric acid cycle

Interpretation Introduction

(b) Interpretation:

The μ moles of acetaldehyde required to allow complete oxidation of the pyruvate to 15 μ moles of CO₂ should be calculated.

Concept introduction:

Pyruvate produced in glycolysis of glucose is oxidised to carbon dioxide and water through a sequence of complicated reaction cycle, popularly named as Krebs cycle. Citric acid and some other tricarboxylic acids occur in the intermediate steps of this reaction sequence; hence the name citric acid cycle and tricarboxylic acid cycle are also given. It is through this cycle of reactions that all food stuff and nutrients are completely oxidised in the cell. All food stuff including carbohydrate must be converted to pyruvate or some other intermediate products for theiroxidation to carbon dioxide and water.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 4

Question

Chapter 13, Problem 7P

Interpretation Introduction

(a) Interpretation:

Assuming the solution containing the 5 μ moles of pyruvate dehydrogenase complex and 5 μ moles of all the enzymes of citric acid cycle but none of the metabolic intermediates. This will generate 5 μ moles of CO₂ and then reaction stops. The reason for production more CO₂ after addition of alcohol dehydrogenase and acetaldehyde should be explained.

Concept introduction:

Pyruvate produced in glycolysis of glucose is oxidised to carbon dioxide and water through a sequence of complicated reaction cycle, popularly named as Krebs cycle. Citric acid and some other tricarboxylic acids occur in the intermediate steps of this reaction sequence, hence the name citric acid cycle and tricarboxylic acid cycle are also given. It is through this cycle of reactions that all food stuff and nutrients are completely oxidised in the cell. All food stuff including carbohydrate must be converted to pyruvate or some other intermediate products for theiroxidation to carbon dioxide and water.

Pictorial representation:

The citric acid cycle with all the reagent and enzymes and metabolic enzymes can be shown as follows:

Figure: Citric acid cycle

Interpretation Introduction

(b) Interpretation:

The μ moles of acetaldehyde required to allow complete oxidation of the pyruvate to 15 μ moles of CO₂ should be calculated.

Concept introduction:

Pyruvate produced in glycolysis of glucose is oxidised to carbon dioxide and water through a sequence of complicated reaction cycle, popularly named as Krebs cycle. Citric acid and some other tricarboxylic acids occur in the intermediate steps of this reaction sequence; hence the name citric acid cycle and tricarboxylic acid cycle are also given. It is through this cycle of reactions that all food stuff and nutrients are completely oxidised in the cell. All food stuff including carbohydrate must be converted to pyruvate or some other intermediate products for theiroxidation to carbon dioxide and water.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 5

Chapter 13, Problem 7P

Interpretation Introduction

(a) Interpretation:

Assuming the solution containing the 5 μ moles of pyruvate dehydrogenase complex and 5 μ moles of all the enzymes of citric acid cycle but none of the metabolic intermediates. This will generate 5 μ moles of CO₂ and then reaction stops. The reason for production more CO₂ after addition of alcohol dehydrogenase and acetaldehyde should be explained.

Concept introduction:

Pyruvate produced in glycolysis of glucose is oxidised to carbon dioxide and water through a sequence of complicated reaction cycle, popularly named as Krebs cycle. Citric acid and some other tricarboxylic acids occur in the intermediate steps of this reaction sequence, hence the name citric acid cycle and tricarboxylic acid cycle are also given. It is through this cycle of reactions that all food stuff and nutrients are completely oxidised in the cell. All food stuff including carbohydrate must be converted to pyruvate or some other intermediate products for theiroxidation to carbon dioxide and water.

Pictorial representation:

The citric acid cycle with all the reagent and enzymes and metabolic enzymes can be shown as follows:

Figure: Citric acid cycle

Interpretation Introduction

(b) Interpretation:

The μ moles of acetaldehyde required to allow complete oxidation of the pyruvate to 15 μ moles of CO₂ should be calculated.

Concept introduction:

Pyruvate produced in glycolysis of glucose is oxidised to carbon dioxide and water through a sequence of complicated reaction cycle, popularly named as Krebs cycle. Citric acid and some other tricarboxylic acids occur in the intermediate steps of this reaction sequence; hence the name citric acid cycle and tricarboxylic acid cycle are also given. It is through this cycle of reactions that all food stuff and nutrients are completely oxidised in the cell. All food stuff including carbohydrate must be converted to pyruvate or some other intermediate products for theiroxidation to carbon dioxide and water.

Answer 6

Chapter 13, Problem 7P

Interpretation Introduction

(a) Interpretation:

Assuming the solution containing the 5 μ moles of pyruvate dehydrogenase complex and 5 μ moles of all the enzymes of citric acid cycle but none of the metabolic intermediates. This will generate 5 μ moles of CO₂ and then reaction stops. The reason for production more CO₂ after addition of alcohol dehydrogenase and acetaldehyde should be explained.

Concept introduction:

Pyruvate produced in glycolysis of glucose is oxidised to carbon dioxide and water through a sequence of complicated reaction cycle, popularly named as Krebs cycle. Citric acid and some other tricarboxylic acids occur in the intermediate steps of this reaction sequence, hence the name citric acid cycle and tricarboxylic acid cycle are also given. It is through this cycle of reactions that all food stuff and nutrients are completely oxidised in the cell. All food stuff including carbohydrate must be converted to pyruvate or some other intermediate products for theiroxidation to carbon dioxide and water.

Pictorial representation:

The citric acid cycle with all the reagent and enzymes and metabolic enzymes can be shown as follows:

Figure: Citric acid cycle

Answer 7

Chapter 13, Problem 7P

Interpretation Introduction

(a) Interpretation:

Assuming the solution containing the 5 μ moles of pyruvate dehydrogenase complex and 5 μ moles of all the enzymes of citric acid cycle but none of the metabolic intermediates. This will generate 5 μ moles of CO₂ and then reaction stops. The reason for production more CO₂ after addition of alcohol dehydrogenase and acetaldehyde should be explained.

Concept introduction:

Pyruvate produced in glycolysis of glucose is oxidised to carbon dioxide and water through a sequence of complicated reaction cycle, popularly named as Krebs cycle. Citric acid and some other tricarboxylic acids occur in the intermediate steps of this reaction sequence, hence the name citric acid cycle and tricarboxylic acid cycle are also given. It is through this cycle of reactions that all food stuff and nutrients are completely oxidised in the cell. All food stuff including carbohydrate must be converted to pyruvate or some other intermediate products for theiroxidation to carbon dioxide and water.

Pictorial representation:

The citric acid cycle with all the reagent and enzymes and metabolic enzymes can be shown as follows:

Figure: Citric acid cycle

Answer 8

Interpretation Introduction

(b) Interpretation:

The μ moles of acetaldehyde required to allow complete oxidation of the pyruvate to 15 μ moles of CO₂ should be calculated.

Concept introduction:

Pyruvate produced in glycolysis of glucose is oxidised to carbon dioxide and water through a sequence of complicated reaction cycle, popularly named as Krebs cycle. Citric acid and some other tricarboxylic acids occur in the intermediate steps of this reaction sequence; hence the name citric acid cycle and tricarboxylic acid cycle are also given. It is through this cycle of reactions that all food stuff and nutrients are completely oxidised in the cell. All food stuff including carbohydrate must be converted to pyruvate or some other intermediate products for theiroxidation to carbon dioxide and water.

Answer 9

Interpretation Introduction

(b) Interpretation:

The μ moles of acetaldehyde required to allow complete oxidation of the pyruvate to 15 μ moles of CO₂ should be calculated.

Concept introduction:

Pyruvate produced in glycolysis of glucose is oxidised to carbon dioxide and water through a sequence of complicated reaction cycle, popularly named as Krebs cycle. Citric acid and some other tricarboxylic acids occur in the intermediate steps of this reaction sequence; hence the name citric acid cycle and tricarboxylic acid cycle are also given. It is through this cycle of reactions that all food stuff and nutrients are completely oxidised in the cell. All food stuff including carbohydrate must be converted to pyruvate or some other intermediate products for theiroxidation to carbon dioxide and water.

Answer 10

Expert Solution & Answer

Answer 11

Expert Solution & Answer

Answer 12

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 13

Ch. 13 - Prob. 1P Ch. 13 - Prob. 2P Ch. 13 - Suppose that aconitase did not bind its substrate...Ch. 13 - Prob. 4P Ch. 13 - Prob. 5P Ch. 13 - Prob. 6P Ch. 13 - Prob. 7P Ch. 13 - Prob. 8P Ch. 13 - Prob. 9P Ch. 13 - Prob. 10P

Concept explainers

Videos

Want to see the full answer?

Chapter 13 Solutions