Chemistry: The Molecular Science
5th Edition
ISBN: 9781285199047
Author: John W. Moore, Conrad L. Stanitski
Publisher: Cengage Learning
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Chapter 13, Problem 73QRT
The freezing point of p-dichlorobenzene is 53.1 °C, and its Kf is –7.10 °C kg/mol. A solution of 1.52 g of the drug sulfanilamide in 10.0 g p-dichlorobenzene freezes at 46.7 °C. Calculate the molar mass of sulfanilamide.
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Chapter 13 Solutions
Chemistry: The Molecular Science
Ch. 13.1 - How could the data in Table 13.2 be used to...Ch. 13.1 - Prob. 13.2CECh. 13.1 - Prob. 13.1PSPCh. 13.1 - Prob. 13.2PSPCh. 13.2 - Prob. 13.3ECh. 13.2 - Determine whether each of these masses of NH4Cl...Ch. 13.4 - Prob. 13.5CECh. 13.4 - Explain why water that has been used to cool a...Ch. 13.4 - If a substance has a positive enthalpy of...Ch. 13.5 - Suppose that a trout stream at 25 C is in...
Ch. 13.6 - Prob. 13.4PSPCh. 13.6 - Prob. 13.8ECh. 13.6 - Drinking water may contain small quantities of...Ch. 13.6 - Prob. 13.9CECh. 13.6 - A 500-mL bottle of Evian bottled water contains 12...Ch. 13.6 - The mass fraction of gold in seawater is 1 103...Ch. 13.6 - Prob. 13.6PSPCh. 13.6 - Prob. 13.7PSPCh. 13.6 - Prob. 13.8PSPCh. 13.6 - Prob. 13.9PSPCh. 13.6 - Prob. 13.12ECh. 13.6 - Prob. 13.13CECh. 13.7 - The vapor pressure of an aqueous solution of urea....Ch. 13.7 - Prob. 13.14ECh. 13.7 - Prob. 13.15ECh. 13.7 - Prob. 13.11PSPCh. 13.7 - Suppose that you are closing a cabin in the north...Ch. 13.7 - A student determines the freezing point to be 5.15...Ch. 13.7 - Prob. 13.17CECh. 13.7 - Prob. 13.13PSPCh. 13.9 - Prob. 13.18CECh. 13.10 - Prob. 13.19ECh. 13.10 - Prob. 13.20ECh. 13 - Prob. 1QRTCh. 13 - Prob. 2QRTCh. 13 - Prob. 3QRTCh. 13 - Prob. 4QRTCh. 13 - Prob. 5QRTCh. 13 - Prob. 6QRTCh. 13 - Prob. 7QRTCh. 13 - Prob. 8QRTCh. 13 - Prob. 9QRTCh. 13 - Prob. 10QRTCh. 13 - Prob. 11QRTCh. 13 - Prob. 12QRTCh. 13 - Prob. 13QRTCh. 13 - Prob. 14QRTCh. 13 - Beakers (a), (b), and (c) are representations of...Ch. 13 - Prob. 16QRTCh. 13 - Simple acids such as formic acid, HCOOH, and...Ch. 13 - Prob. 18QRTCh. 13 - Prob. 19QRTCh. 13 - Prob. 20QRTCh. 13 - Prob. 21QRTCh. 13 - Prob. 22QRTCh. 13 - Prob. 23QRTCh. 13 - Prob. 24QRTCh. 13 - Prob. 25QRTCh. 13 - Prob. 26QRTCh. 13 - Refer to Figure 13.10 ( Sec. 13-4b) to answer...Ch. 13 - Prob. 28QRTCh. 13 - Prob. 29QRTCh. 13 - Prob. 30QRTCh. 13 - The Henrys law constant for nitrogen in blood...Ch. 13 - Prob. 32QRTCh. 13 - Prob. 33QRTCh. 13 - Prob. 34QRTCh. 13 - Prob. 35QRTCh. 13 - Prob. 36QRTCh. 13 - Prob. 37QRTCh. 13 - Prob. 38QRTCh. 13 - Prob. 39QRTCh. 13 - Prob. 40QRTCh. 13 - A sample of water contains 0.010 ppm lead ions,...Ch. 13 - Prob. 42QRTCh. 13 - Prob. 43QRTCh. 13 - Prob. 44QRTCh. 13 - Prob. 45QRTCh. 13 - Prob. 46QRTCh. 13 - Prob. 47QRTCh. 13 - Prob. 48QRTCh. 13 - Prob. 49QRTCh. 13 - Prob. 50QRTCh. 13 - Consider a 13.0% solution of sulfuric acid,...Ch. 13 - You want to prepare a 1.0 mol/kg solution of...Ch. 13 - Prob. 53QRTCh. 13 - Prob. 54QRTCh. 13 - Prob. 55QRTCh. 13 - A 12-oz (355-mL) Pepsi contains 38.9 mg...Ch. 13 - Prob. 57QRTCh. 13 - Prob. 58QRTCh. 13 - Prob. 59QRTCh. 13 - Prob. 60QRTCh. 13 - Prob. 61QRTCh. 13 - Prob. 62QRTCh. 13 - Prob. 63QRTCh. 13 - Prob. 64QRTCh. 13 - Prob. 65QRTCh. 13 - Prob. 66QRTCh. 13 - Calculate the boiling point and the freezing point...Ch. 13 - Prob. 68QRTCh. 13 - Prob. 69QRTCh. 13 - Prob. 70QRTCh. 13 - Prob. 71QRTCh. 13 - Prob. 72QRTCh. 13 - The freezing point of p-dichlorobenzene is 53.1 C,...Ch. 13 - Prob. 74QRTCh. 13 - Prob. 75QRTCh. 13 - A 1.00 mol/kg aqueous sulfuric acid solution,...Ch. 13 - Prob. 77QRTCh. 13 - Prob. 78QRTCh. 13 - Prob. 79QRTCh. 13 - Prob. 80QRTCh. 13 - Prob. 81QRTCh. 13 - Differentiate between the dispersed phase and the...Ch. 13 - Prob. 83QRTCh. 13 - Prob. 84QRTCh. 13 - Prob. 85QRTCh. 13 - Prob. 86QRTCh. 13 - Prob. 87QRTCh. 13 - Prob. 88QRTCh. 13 - Prob. 89QRTCh. 13 - Prob. 90QRTCh. 13 - Prob. 91QRTCh. 13 - Prob. 92QRTCh. 13 - Prob. 93QRTCh. 13 - Prob. 94QRTCh. 13 - Prob. 95QRTCh. 13 - Prob. 96QRTCh. 13 - Prob. 97QRTCh. 13 - Prob. 98QRTCh. 13 - Prob. 99QRTCh. 13 - Prob. 100QRTCh. 13 - Prob. 101QRTCh. 13 - Prob. 102QRTCh. 13 - In The Rime of the Ancient Mariner the poet Samuel...Ch. 13 - Prob. 104QRTCh. 13 - Prob. 105QRTCh. 13 - Calculate the molality of a solution made by...Ch. 13 - Prob. 107QRTCh. 13 - Prob. 108QRTCh. 13 - Prob. 109QRTCh. 13 - Prob. 110QRTCh. 13 - The organic salt [(C4H9)4N][ClO4] consists of the...Ch. 13 - A solution, prepared by dissolving 9.41 g NaHSO3...Ch. 13 - A 0.250-M sodium sulfate solution is added to a...Ch. 13 - Prob. 114QRTCh. 13 - Prob. 115QRTCh. 13 - Prob. 116QRTCh. 13 - Prob. 117QRTCh. 13 - Prob. 118QRTCh. 13 - Prob. 119QRTCh. 13 - Refer to Figure 13.10 ( Sec. 13-4b) to determine...Ch. 13 - Prob. 121QRTCh. 13 - Prob. 122QRTCh. 13 - Prob. 123QRTCh. 13 - Prob. 124QRTCh. 13 - In your own words, explain why (a) seawater has a...Ch. 13 - Prob. 126QRTCh. 13 - Prob. 127QRTCh. 13 - Prob. 128QRTCh. 13 - Prob. 129QRTCh. 13 - Prob. 130QRTCh. 13 - Prob. 131QRTCh. 13 - A 0.109 mol/kg aqueous solution of formic...Ch. 13 - Prob. 133QRTCh. 13 - Maple syrup sap is 3% sugar (sucrose) and 97%...Ch. 13 - Prob. 137QRTCh. 13 - Prob. 13.ACPCh. 13 - Prob. 13.BCPCh. 13 - Prob. 13.CCP
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- Part II. two unbranched ketone have molecular formulla (C8H100). El-ms showed that both of them have a molecular ion peak at m/2 =128. However ketone (A) has a fragment peak at m/2 = 99 and 72 while ketone (B) snowed a fragment peak at m/2 = 113 and 58. 9) Propose the most plausible structures for both ketones b) Explain how you arrived at your conclusion by drawing the Structures of the distinguishing fragments for each ketone, including their fragmentation mechanisms.arrow_forwardPart V. Draw the structure of compound tecla using the IR spectrum Cobtained from the compound in KBr pellet) and the mass spectrum as shown below. The mass spectrum of compound Tesla showed strong mt peak at 71. TRANSMITTANCE LOD Relative Intensity 100 MS-NW-1539 40 20 80 T 44 55 10 15 20 25 30 35 40 45 50 55 60 65 70 75 m/z D 4000 3000 2000 1500 1000 500 HAVENUMBERI-11arrow_forwardTechnetium is the first element in the periodic chart that does not have any stable isotopes. Technetium-99m is an especially interesting and valuable isotope as it emits a gamma ray with a half life ideally suited for medical tests. It would seem that the decay of technetium should fit the treatment above with the result In(c/c) = -kt. The table below includes data from the two sites: http://dailymed.nlm.nih.gov/dailymed/druginfo.cfm?id=7130 http://wiki.medpedia.com/Clinical: Neutrospec_(Technetium_(99m Tc)_fanolesomab). a. b. C. Graph the fraction (c/c.) on the vertical axis versus the time on the horizontal axis. Also graph In(c/c.) on the vertical axis versus time on the horizontal axis. When half of the original amount of starting material has hours fraction remaining disappeared, c/c = ½ and the equation In(c/c.) = -kt becomes In(0.5) = -kt1/2 where t₁₂ is the half life (the time for half of the material to decay away). Determine the slope of your In(c/c.) vs t graph and…arrow_forward
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Solutions: Crash Course Chemistry #27; Author: Crash Course;https://www.youtube.com/watch?v=9h2f1Bjr0p4;License: Standard YouTube License, CC-BY