Chemistry: The Molecular Science
Chemistry: The Molecular Science
5th Edition
ISBN: 9781285199047
Author: John W. Moore, Conrad L. Stanitski
Publisher: Cengage Learning
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Chapter 13, Problem 59QRT

(a)

Interpretation Introduction

Interpretation: The mass fraction and weight percent of K2CrO4 has to be calculated.

Concept introduction:

Mass fraction: The mass of a single solute divided by the total mass of all solutes and solvent in the solution.

  Mass fraction of A = Mass of A Mass ofA + Mass ofB + Mass ofC+ ....

Weight percent: The mass of one component divided by the total mass of the mixture, multiplied by 100%

  weight % A = Mass of A Mass of A + Mass of B + Mass of C + ...×100%.

(a)

Expert Solution
Check Mark

Answer to Problem 59QRT

The mass fraction of K2CrO4 is 0.0586 and weight percent of K2CrO4 is calculated as 5.86 %.

Explanation of Solution

  • The Mass fraction:

  Mass fraction of A = Mass of A Mass ofA + Mass ofB + Mass ofC+ ....

Given information as: Mass of K2CrO4 is 14.0 g and pure water is  225g.

Mass fraction of K2CrO4Mass of K2CrO4Mass ofK2CrO4 + Mass ofwater 

  14.0 g(14.0g+ 225g) = 0.0586.

Hence, the mass fraction of K2CrO4 is 0.0586.

  • The Weight percent:

  weight % A = Mass of A Mass of A + Mass of B + Mass of C + ...×100%.

Given information as: Mass of K2CrO4 is 14.0 g and pure water is  225g.

  weight % of K2CrO4=Mass of K2CrO4 Mass ofK2CrO4 + Mass ofwater ×100%=(0.0586)×100% = 5.86 %.

The weight percent of K2CrO4 is calculated as shown above. Hence, the weight percent obtained is 5.86 %.

(b)

Interpretation Introduction

Interpretation: The mass fraction and weight percent of ethanol has to be calculated.

Concept introduction:

Refer to (a)

(b)

Expert Solution
Check Mark

Answer to Problem 59QRT

The mass fraction of ethanol is 0.0836 and weight percent of ethanol is calculated as 8.36 %.

Explanation of Solution

  • The Mass fraction:

  Mass fraction of A = Mass of A Mass ofA + Mass ofB + Mass ofC+ ....

Given information as: Mass of ethanol is 4.56 g ; benzene is 50.0g.

Mass fraction of ethanol Mass of ethanolMass ofethanol + Mass ofbenzene 

  4.56g(4.56g+ 50.0g) = 0.0836.

Hence, the mass fraction of ethanol is 0.0836.

  • The Weight percent:

  weight % A = Mass of A Mass of A + Mass of B + Mass of C + ...×100%.

Given information as: Mass of ethanol is 4.56 g ; benzene is 50.0g.

  weight % of ethanol=Mass of ethanol Mass ofethanol+Mass ofbenzene ×100%=(0.0836)×100% = 8.36 %.

The weight percent of ethanol is calculated as shown above. Hence, the weight percent obtained is 8.36 %.

(c)

Interpretation Introduction

Interpretation: The mass fraction and weight percent of methanol has to be calculated.

Concept introduction:

Refer to (a)

(c)

Expert Solution
Check Mark

Answer to Problem 59QRT

The mass fraction of methanol is 0.144 and weight percent of methanol is calculated as 30.8 %.

Explanation of Solution

  • The Mass fraction:

  Mass fraction of A = Mass of A Mass ofA + Mass ofB + Mass ofC+ ....

Given information as: Mass of methanol is 15.0 g and pure ethanol 89.0 g.

Mass fraction of methanol Mass of methanolMass ofmethanol+ Mass ofethanol 

  15.0 g(15.0g+89.0g) = 0.144.

Hence, the mass fraction of methanol is 0.144.

  • The Weight percent:

  weight % A = Mass of A Mass of A + Mass of B + Mass of C + ...×100%.

Given information as: Mass of methanol is 15.0 g and pure ethanol 89.0 g.

  weight % of methanol=Mass of methanol Mass ofmethanol+Mass ofethanol ×100%=(0.144)×100% = 14.4%.

The weight percent of methanol is calculated as shown above. Hence, the weight percent obtained is 14.4%.

(d)

Interpretation Introduction

Interpretation: The mass fraction and weight percent of ethylene glycol has to be calculated.

Concept introduction:

Refer to (a)

(d)

Expert Solution
Check Mark

Answer to Problem 59QRT

The mass fraction of ethylene glycol is 0.0744 and weight percent of ethylene glycol is calculated as 7.4 %.

Explanation of Solution

  • The Mass fraction:

  Mass fraction of A = Mass of A Mass ofA + Mass ofB + Mass ofC+ ....

Given information as: Density of ethylene glycol is 1.11 g/mL ; volume is 14.5 mL and water is 200g.

Mass of ethylene glycol: Density×Volume

  =(1.11g/mL)(14.5mL)=16.095g.

Mass fraction of ethylene glycol Mass of ethylene glycolMass ofethylene glycol + Mass ofWater 

  16.095g(16.095g+ 200.0g) = 0.0744.

Hence, the mass fraction of ethylene glycol is 0.0744.

  • The Weight percent:

  weight % A = Mass of A Mass of A + Mass of B + Mass of C + ...×100%.

  weight % of ethylene glycol=Mass of ethylene glycol Mass ofethylene glycol+Mass ofwater ×100%=(0.0744)×100% = 7.4 %.

The weight percent of ethylene glycol is calculated as shown above. Hence, the weight percent obtained is 7.4 %.

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Chapter 13 Solutions

Chemistry: The Molecular Science

Ch. 13.6 - Prob. 13.4PSPCh. 13.6 - Prob. 13.8ECh. 13.6 - Drinking water may contain small quantities of...Ch. 13.6 - Prob. 13.9CECh. 13.6 - A 500-mL bottle of Evian bottled water contains 12...Ch. 13.6 - The mass fraction of gold in seawater is 1 103...Ch. 13.6 - Prob. 13.6PSPCh. 13.6 - Prob. 13.7PSPCh. 13.6 - Prob. 13.8PSPCh. 13.6 - Prob. 13.9PSPCh. 13.6 - Prob. 13.12ECh. 13.6 - Prob. 13.13CECh. 13.7 - The vapor pressure of an aqueous solution of urea....Ch. 13.7 - Prob. 13.14ECh. 13.7 - Prob. 13.15ECh. 13.7 - Prob. 13.11PSPCh. 13.7 - Suppose that you are closing a cabin in the north...Ch. 13.7 - A student determines the freezing point to be 5.15...Ch. 13.7 - Prob. 13.17CECh. 13.7 - Prob. 13.13PSPCh. 13.9 - Prob. 13.18CECh. 13.10 - Prob. 13.19ECh. 13.10 - Prob. 13.20ECh. 13 - Prob. 1QRTCh. 13 - Prob. 2QRTCh. 13 - Prob. 3QRTCh. 13 - Prob. 4QRTCh. 13 - Prob. 5QRTCh. 13 - Prob. 6QRTCh. 13 - Prob. 7QRTCh. 13 - Prob. 8QRTCh. 13 - Prob. 9QRTCh. 13 - Prob. 10QRTCh. 13 - Prob. 11QRTCh. 13 - Prob. 12QRTCh. 13 - Prob. 13QRTCh. 13 - Prob. 14QRTCh. 13 - Beakers (a), (b), and (c) are representations of...Ch. 13 - Prob. 16QRTCh. 13 - Simple acids such as formic acid, HCOOH, and...Ch. 13 - Prob. 18QRTCh. 13 - Prob. 19QRTCh. 13 - Prob. 20QRTCh. 13 - Prob. 21QRTCh. 13 - Prob. 22QRTCh. 13 - Prob. 23QRTCh. 13 - Prob. 24QRTCh. 13 - Prob. 25QRTCh. 13 - Prob. 26QRTCh. 13 - Refer to Figure 13.10 ( Sec. 13-4b) to answer...Ch. 13 - Prob. 28QRTCh. 13 - Prob. 29QRTCh. 13 - Prob. 30QRTCh. 13 - The Henrys law constant for nitrogen in blood...Ch. 13 - Prob. 32QRTCh. 13 - Prob. 33QRTCh. 13 - Prob. 34QRTCh. 13 - Prob. 35QRTCh. 13 - Prob. 36QRTCh. 13 - Prob. 37QRTCh. 13 - Prob. 38QRTCh. 13 - Prob. 39QRTCh. 13 - Prob. 40QRTCh. 13 - A sample of water contains 0.010 ppm lead ions,...Ch. 13 - Prob. 42QRTCh. 13 - Prob. 43QRTCh. 13 - Prob. 44QRTCh. 13 - Prob. 45QRTCh. 13 - Prob. 46QRTCh. 13 - Prob. 47QRTCh. 13 - Prob. 48QRTCh. 13 - Prob. 49QRTCh. 13 - Prob. 50QRTCh. 13 - Consider a 13.0% solution of sulfuric acid,...Ch. 13 - You want to prepare a 1.0 mol/kg solution of...Ch. 13 - Prob. 53QRTCh. 13 - Prob. 54QRTCh. 13 - Prob. 55QRTCh. 13 - A 12-oz (355-mL) Pepsi contains 38.9 mg...Ch. 13 - Prob. 57QRTCh. 13 - Prob. 58QRTCh. 13 - Prob. 59QRTCh. 13 - Prob. 60QRTCh. 13 - Prob. 61QRTCh. 13 - Prob. 62QRTCh. 13 - Prob. 63QRTCh. 13 - Prob. 64QRTCh. 13 - Prob. 65QRTCh. 13 - Prob. 66QRTCh. 13 - Calculate the boiling point and the freezing point...Ch. 13 - Prob. 68QRTCh. 13 - Prob. 69QRTCh. 13 - Prob. 70QRTCh. 13 - Prob. 71QRTCh. 13 - Prob. 72QRTCh. 13 - The freezing point of p-dichlorobenzene is 53.1 C,...Ch. 13 - Prob. 74QRTCh. 13 - Prob. 75QRTCh. 13 - A 1.00 mol/kg aqueous sulfuric acid solution,...Ch. 13 - Prob. 77QRTCh. 13 - Prob. 78QRTCh. 13 - Prob. 79QRTCh. 13 - Prob. 80QRTCh. 13 - Prob. 81QRTCh. 13 - Differentiate between the dispersed phase and the...Ch. 13 - Prob. 83QRTCh. 13 - Prob. 84QRTCh. 13 - Prob. 85QRTCh. 13 - Prob. 86QRTCh. 13 - Prob. 87QRTCh. 13 - Prob. 88QRTCh. 13 - Prob. 89QRTCh. 13 - Prob. 90QRTCh. 13 - Prob. 91QRTCh. 13 - Prob. 92QRTCh. 13 - Prob. 93QRTCh. 13 - Prob. 94QRTCh. 13 - Prob. 95QRTCh. 13 - Prob. 96QRTCh. 13 - Prob. 97QRTCh. 13 - Prob. 98QRTCh. 13 - Prob. 99QRTCh. 13 - Prob. 100QRTCh. 13 - Prob. 101QRTCh. 13 - Prob. 102QRTCh. 13 - In The Rime of the Ancient Mariner the poet Samuel...Ch. 13 - Prob. 104QRTCh. 13 - Prob. 105QRTCh. 13 - Calculate the molality of a solution made by...Ch. 13 - Prob. 107QRTCh. 13 - Prob. 108QRTCh. 13 - Prob. 109QRTCh. 13 - Prob. 110QRTCh. 13 - The organic salt [(C4H9)4N][ClO4] consists of the...Ch. 13 - A solution, prepared by dissolving 9.41 g NaHSO3...Ch. 13 - A 0.250-M sodium sulfate solution is added to a...Ch. 13 - Prob. 114QRTCh. 13 - Prob. 115QRTCh. 13 - Prob. 116QRTCh. 13 - Prob. 117QRTCh. 13 - Prob. 118QRTCh. 13 - Prob. 119QRTCh. 13 - Refer to Figure 13.10 ( Sec. 13-4b) to determine...Ch. 13 - Prob. 121QRTCh. 13 - Prob. 122QRTCh. 13 - Prob. 123QRTCh. 13 - Prob. 124QRTCh. 13 - In your own words, explain why (a) seawater has a...Ch. 13 - Prob. 126QRTCh. 13 - Prob. 127QRTCh. 13 - Prob. 128QRTCh. 13 - Prob. 129QRTCh. 13 - Prob. 130QRTCh. 13 - Prob. 131QRTCh. 13 - A 0.109 mol/kg aqueous solution of formic...Ch. 13 - Prob. 133QRTCh. 13 - Maple syrup sap is 3% sugar (sucrose) and 97%...Ch. 13 - Prob. 137QRTCh. 13 - Prob. 13.ACPCh. 13 - Prob. 13.BCPCh. 13 - Prob. 13.CCP
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Solutions: Crash Course Chemistry #27; Author: Crash Course;https://www.youtube.com/watch?v=9h2f1Bjr0p4;License: Standard YouTube License, CC-BY