Chemistry: The Molecular Science
Chemistry: The Molecular Science
5th Edition
ISBN: 9781285199047
Author: John W. Moore, Conrad L. Stanitski
Publisher: Cengage Learning
Question
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Chapter 13, Problem 1QRT
Interpretation Introduction

Interpretation:

The motor oil and gasoline are miscible; the reason has to be predicted.

Concept introduction:

Like dissolves like principle: ‘Like dissolves like’ principle says that polar compounds including ionic compound should be more soluble in polar solvent.  Likewise, non–polar compound should be more soluble in non–polar solvent.

Polar molecule: Polar molecules have large dipole moments.

Non-Polar molecules: Non-polar molecules have bonded atoms with similar electronegativity results to have zero dipole moments.

Solubility is the quantity of solute (solid, liquid or gas) that will dissolve in a given amount of solvent (solid, liquid or gas) at definite temperature and pressure.  Solubility depends on the physical and chemical property of solvent, solute and concentration of the solution.

Expert Solution & Answer
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Explanation of Solution

From the two given molecule namely motor oil and gasoline; motor oil is non-polar. Gasoline is also non-polar molecule as both are hydrocarbons. According to ‘like dissolves like’ principle, the gasoline and motor oil possess same interactions.

Therefore, motor oil is readily soluble in gasoline.

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Chapter 13 Solutions

Chemistry: The Molecular Science

Ch. 13.6 - Prob. 13.4PSPCh. 13.6 - Prob. 13.8ECh. 13.6 - Drinking water may contain small quantities of...Ch. 13.6 - Prob. 13.9CECh. 13.6 - A 500-mL bottle of Evian bottled water contains 12...Ch. 13.6 - The mass fraction of gold in seawater is 1 103...Ch. 13.6 - Prob. 13.6PSPCh. 13.6 - Prob. 13.7PSPCh. 13.6 - Prob. 13.8PSPCh. 13.6 - Prob. 13.9PSPCh. 13.6 - Prob. 13.12ECh. 13.6 - Prob. 13.13CECh. 13.7 - The vapor pressure of an aqueous solution of urea....Ch. 13.7 - Prob. 13.14ECh. 13.7 - Prob. 13.15ECh. 13.7 - Prob. 13.11PSPCh. 13.7 - Suppose that you are closing a cabin in the north...Ch. 13.7 - A student determines the freezing point to be 5.15...Ch. 13.7 - Prob. 13.17CECh. 13.7 - Prob. 13.13PSPCh. 13.9 - Prob. 13.18CECh. 13.10 - Prob. 13.19ECh. 13.10 - Prob. 13.20ECh. 13 - Prob. 1QRTCh. 13 - Prob. 2QRTCh. 13 - Prob. 3QRTCh. 13 - Prob. 4QRTCh. 13 - Prob. 5QRTCh. 13 - Prob. 6QRTCh. 13 - Prob. 7QRTCh. 13 - Prob. 8QRTCh. 13 - Prob. 9QRTCh. 13 - Prob. 10QRTCh. 13 - Prob. 11QRTCh. 13 - Prob. 12QRTCh. 13 - Prob. 13QRTCh. 13 - Prob. 14QRTCh. 13 - Beakers (a), (b), and (c) are representations of...Ch. 13 - Prob. 16QRTCh. 13 - Simple acids such as formic acid, HCOOH, and...Ch. 13 - Prob. 18QRTCh. 13 - Prob. 19QRTCh. 13 - Prob. 20QRTCh. 13 - Prob. 21QRTCh. 13 - Prob. 22QRTCh. 13 - Prob. 23QRTCh. 13 - Prob. 24QRTCh. 13 - Prob. 25QRTCh. 13 - Prob. 26QRTCh. 13 - Refer to Figure 13.10 ( Sec. 13-4b) to answer...Ch. 13 - Prob. 28QRTCh. 13 - Prob. 29QRTCh. 13 - Prob. 30QRTCh. 13 - The Henrys law constant for nitrogen in blood...Ch. 13 - Prob. 32QRTCh. 13 - Prob. 33QRTCh. 13 - Prob. 34QRTCh. 13 - Prob. 35QRTCh. 13 - Prob. 36QRTCh. 13 - Prob. 37QRTCh. 13 - Prob. 38QRTCh. 13 - Prob. 39QRTCh. 13 - Prob. 40QRTCh. 13 - A sample of water contains 0.010 ppm lead ions,...Ch. 13 - Prob. 42QRTCh. 13 - Prob. 43QRTCh. 13 - Prob. 44QRTCh. 13 - Prob. 45QRTCh. 13 - Prob. 46QRTCh. 13 - Prob. 47QRTCh. 13 - Prob. 48QRTCh. 13 - Prob. 49QRTCh. 13 - Prob. 50QRTCh. 13 - Consider a 13.0% solution of sulfuric acid,...Ch. 13 - You want to prepare a 1.0 mol/kg solution of...Ch. 13 - Prob. 53QRTCh. 13 - Prob. 54QRTCh. 13 - Prob. 55QRTCh. 13 - A 12-oz (355-mL) Pepsi contains 38.9 mg...Ch. 13 - Prob. 57QRTCh. 13 - Prob. 58QRTCh. 13 - Prob. 59QRTCh. 13 - Prob. 60QRTCh. 13 - Prob. 61QRTCh. 13 - Prob. 62QRTCh. 13 - Prob. 63QRTCh. 13 - Prob. 64QRTCh. 13 - Prob. 65QRTCh. 13 - Prob. 66QRTCh. 13 - Calculate the boiling point and the freezing point...Ch. 13 - Prob. 68QRTCh. 13 - Prob. 69QRTCh. 13 - Prob. 70QRTCh. 13 - Prob. 71QRTCh. 13 - Prob. 72QRTCh. 13 - The freezing point of p-dichlorobenzene is 53.1 C,...Ch. 13 - Prob. 74QRTCh. 13 - Prob. 75QRTCh. 13 - A 1.00 mol/kg aqueous sulfuric acid solution,...Ch. 13 - Prob. 77QRTCh. 13 - Prob. 78QRTCh. 13 - Prob. 79QRTCh. 13 - Prob. 80QRTCh. 13 - Prob. 81QRTCh. 13 - Differentiate between the dispersed phase and the...Ch. 13 - Prob. 83QRTCh. 13 - Prob. 84QRTCh. 13 - Prob. 85QRTCh. 13 - Prob. 86QRTCh. 13 - Prob. 87QRTCh. 13 - Prob. 88QRTCh. 13 - Prob. 89QRTCh. 13 - Prob. 90QRTCh. 13 - Prob. 91QRTCh. 13 - Prob. 92QRTCh. 13 - Prob. 93QRTCh. 13 - Prob. 94QRTCh. 13 - Prob. 95QRTCh. 13 - Prob. 96QRTCh. 13 - Prob. 97QRTCh. 13 - Prob. 98QRTCh. 13 - Prob. 99QRTCh. 13 - Prob. 100QRTCh. 13 - Prob. 101QRTCh. 13 - Prob. 102QRTCh. 13 - In The Rime of the Ancient Mariner the poet Samuel...Ch. 13 - Prob. 104QRTCh. 13 - Prob. 105QRTCh. 13 - Calculate the molality of a solution made by...Ch. 13 - Prob. 107QRTCh. 13 - Prob. 108QRTCh. 13 - Prob. 109QRTCh. 13 - Prob. 110QRTCh. 13 - The organic salt [(C4H9)4N][ClO4] consists of the...Ch. 13 - A solution, prepared by dissolving 9.41 g NaHSO3...Ch. 13 - A 0.250-M sodium sulfate solution is added to a...Ch. 13 - Prob. 114QRTCh. 13 - Prob. 115QRTCh. 13 - Prob. 116QRTCh. 13 - Prob. 117QRTCh. 13 - Prob. 118QRTCh. 13 - Prob. 119QRTCh. 13 - Refer to Figure 13.10 ( Sec. 13-4b) to determine...Ch. 13 - Prob. 121QRTCh. 13 - Prob. 122QRTCh. 13 - Prob. 123QRTCh. 13 - Prob. 124QRTCh. 13 - In your own words, explain why (a) seawater has a...Ch. 13 - Prob. 126QRTCh. 13 - Prob. 127QRTCh. 13 - Prob. 128QRTCh. 13 - Prob. 129QRTCh. 13 - Prob. 130QRTCh. 13 - Prob. 131QRTCh. 13 - A 0.109 mol/kg aqueous solution of formic...Ch. 13 - Prob. 133QRTCh. 13 - Maple syrup sap is 3% sugar (sucrose) and 97%...Ch. 13 - Prob. 137QRTCh. 13 - Prob. 13.ACPCh. 13 - Prob. 13.BCPCh. 13 - Prob. 13.CCP
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