Chapter 13, Problem 5STP

To determine

The correct option.

Answer to Problem 5STP

Option D.

Explanation of Solution

Given info:

Density of wood, $\rho =1.10\text{}\text{g}/{\text{cm}}^{\text{3}}$

Displaced volume, $V=786\text{mL}$

Formula used:

The net force can be calculated as,

  $F=\rho Vg$

Here,

• $g$ is acceleration due to gravity.

Calculation:

Substitute the given values in the formula.

  $\begin{array}{c}F=\left(1.10\text{}\text{g}/{\text{cm}}^{\text{3}}\right)\left(786\text{}\text{mL}\right)\left(980\text{cm}/{\text{s}}^{\text{2}}\right)\\ =\left(1.10\text{}\text{g}/{\text{cm}}^{\text{3}}\right)\left(\frac{{10}^{-3}\text{}\text{kg}}{1\text{gm}}\right)\left(786\text{}\text{mL}\right)\left(\frac{1\text{}\text{}{\text{cm}}^{\text{3}}}{1\text{g}}\right)\left(980\text{cm}/{\text{s}}^{\text{2}}\right)\\ =8.47\text{N}\end{array}$

Conclusion:

Hence, the applied force is $8.47\text{N}$ .