Chapter 13, Problem 56A

To determine

Ascending order of the pressure.

Answer to Problem 56A

The pressure from least to greatest is: $B<A<E<D<C$ .

Explanation of Solution

Introduction: Pressure is the force applied to the surface per unit area of an object perpendicularly. SI unit of pressure is Pascal.

Pressure is dependent on the force and the area over which the force is applied. It is pressure that measures the amount of force acting upon an area.

  $\text{Pressure=}\frac{\text{Force}}{\text{Area}}$ which means the more is the force, the greater will be the pressure, but more is the area, the smaller will be the pressure.

Calculate the pressure of each:

  $20\text{}N$ exerted over a surface of $0.35m^2$

Put values in the formula:

  $\text{P=}\frac{\text{20}\text{N}}{\text{0}\text{.35}{\text{m}}^{\text{2}}}\text{=57}\text{.14}\text{Pa}$

  $20\text{}N$ exerted over a surface of $0.65m^2$

Put values in the formula:

  $\text{P=}\frac{\text{20}\text{N}}{\text{0}\text{.65}{\text{m}}^{\text{2}}}\text{=30}\text{.76}\text{Pa}$

  $50\text{}N$ exerted over a surface of $0.05m^2$

Put values in the formula:

  $\text{P=}\frac{\text{50}\text{N}}{\text{0}\text{.05}{\text{m}}^{\text{2}}}\text{=1000}\text{Pa}$

  $50\text{}N$ exerted over a surface of $0.35m^2$

Put values in the formula:

  $\text{P=}\frac{\text{50}\text{N}}{\text{0}\text{.35}{\text{m}}^{\text{2}}}\text{=142}\text{Pa}$

  $60\text{}N$ exerted over a surface of $0.55m^2$

Put values in the formula:

  $\text{P=}\frac{\text{60}\text{N}}{\text{0}\text{.55}{\text{m}}^{\text{2}}}\text{=109}\text{Pa}$

Thus, following order is from least to greatest pressure:

  $B<A<E<D<C$ .

Conclusion:Thus, the pressure from least to greatest is: $B<A<E<D<C$