The mechanism for the given reaction has to be proposed. Concept introduction: Radical or free radical: unpaired valence electron of an atom, molecule, or ion is called as radical. Bond strength is depends on the formation of the radical, if the radical is involving in resonance which is weakest bond strength. Radical or free radical: unpaired valence electron of an atom, molecule, or ion is called as radical. Bromination of Allylic Carbons: N-bromosuccinimide (NBS) is used for the allylic bromination through radical reaction. bromination of allylic carbon requires low concentration of bromine and low concentration of hydrobromic acid. If high concentration of bromine and high concentration of hydrobromic acid which leads to the formation of bromination in the double bond. Bromination reaction starts with the homolytic cleavage of N-Br bond in N-bromosuccinimide (NBS) which creates bromine radical to initiate the radical bromination reaction. NBS bromine radical removes the allylic hydrogen which forms hydrogen bromide and allylic radical in the first propagation step, the allylic radical is stabilized by the double bond in ring. This allylic radical reaction with bromine molecule and forms allylic bromide in the second propagation step which are shown above.

Question

Want to see the full answer?

Answer 1

Question

Chapter 13, Problem 32P

Interpretation Introduction

Interpretation:

The mechanism for the given reaction has to be proposed.

Concept introduction:

Radical or free radical: unpaired valence electron of an atom, molecule, or ion is called as radical.

Bond strength is depends on the formation of the radical, if the radical is involving in resonance which is weakest bond strength.

Radical or free radical: unpaired valence electron of an atom, molecule, or ion is called as radical.

Bromination of Allylic Carbons:

N-bromosuccinimide (NBS) is used for the allylic bromination through radical reaction. bromination of allylic carbon requires low concentration of bromine and low concentration of hydrobromic acid. If high concentration of bromine and high concentration of hydrobromic acid which leads to the formation of bromination in the double bond.

Bromination reaction starts with the homolytic cleavage of N-Br bond in N-bromosuccinimide (NBS) which creates bromine radical to initiate the radical bromination reaction.

NBS bromine radical removes the allylic hydrogen which forms hydrogen bromide and allylic radical in the first propagation step, the allylic radical is stabilized by the double bond in ring. This allylic radical reaction with bromine molecule and forms allylic bromide in the second propagation step which are shown above.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

Draw the major product of this reaction ingnore the inorganic byproducts. 1. NaOCH2CH3 at 25 C 2. PhCH2Br (1 eq)

At 90ºC the vapor pressure of ortho-xylene is 20 kPa and that of meta-xylene is 18 kPa. What is the composition of the vapor in equilibrium with a mixture in which the mole fraction of o-xylene is 0.60?

Draw the products of this reduction of a ketone with sodium borohydride. Use a dash or wedge bond to indicate the stereochemistry of substituents on asymmetric centers, where applicableIgnore any inorganic byproducts. 1) NaBH4 2) HCI/H2O Select to Draw