Genetic Analysis: An Integrated Approach (2nd Edition)
2nd Edition
ISBN: 9780321948908
Author: Mark F. Sanders, John L. Bowman
Publisher: PEARSON
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Chapter 13, Problem 30P
After reading Experimental Insight
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Let’s suppose a researcher was interested in the effects of mutationson the expression of a protein-encoding gene for a proteinthat is 472 amino acids in length. This protein is expressed in leafcells of Arabidopsis thaliana. It has a molecular mass of approximately56,640 Da. Make a drawing that shows the expected resultsof a Western blot using proteins isolated from the leaf cells thatwere obtained from the following plants:Lane 1. A plant homozygous for a nonmutant geneLane 2. A plant homozygous for a deletion that removes the promoterfor this geneLane 3. A heterozygous plant in which one gene is nonmutant andthe other gene has a mutation that introduces an early stop codon atcodon 112Lane 4. A plant homozygous for a mutation that introduces anearly stop codon at codon 112Lane 5. A plant homozygous for a mutation that changes codon108 from a phenylalanine codon into a leucine codon
Time mapping is performed in a cross involving the genes his,leu, mal, and xyl. The recipient cells are auxotrophic for all fourgenes. After 25 minutes, mating is interrupted, with the resultsin recipient cells shown below. Diagram the positions of thesegenes relative to the origin (O) of the F factor and to one another.(a) 90% are xyl+(b) 80% are mal+(c) 20% are his+(d) None are leu+
Prototrophy is often the phenotype selected to detecttransformants. Prototrophic cells are used for donorDNA extraction; then this DNA is cloned and the clonesare added to an auxotrophic recipient culture. Successfultransformants are identified by plating the recipientculture on minimal medium and looking for colonies.What experimental design would you use to make surethat a colony that you hope is a transformant is not, infact,a. a prototrophic cell that has entered the recipientculture as a contaminant?b. a revertant (mutation back to prototrophy by a secondmutation in the originally mutated gene) of theauxotrophic mutation?
Chapter 13 Solutions
Genetic Analysis: An Integrated Approach (2nd Edition)
Ch. 13 - Prob. 1PCh. 13 - For one set of chromosomes carried by a triploid...Ch. 13 - 10.8 If the haploid number for a plant species is...Ch. 13 - From the following list, identify the types...Ch. 13 - Mating between a male donkey (2n=64) and a female...Ch. 13 - Prob. 6PCh. 13 - Prob. 7PCh. 13 - What can we conclude about a mutational event...Ch. 13 - 9. In terms of the chromosome content of nuclei,...Ch. 13 - 10. In Drosophila, an X-linked recessive allele...
Ch. 13 - The plants in this problem are the same as those...Ch. 13 - A normal chromosome and its homolog carrying a...Ch. 13 - 10.12 A pair of homologous chromosomes in...Ch. 13 - 10.13 An animal heterozygous for a reciprocal...Ch. 13 - Dr. Ara B. Dopsis has an idea he thinks will be a...Ch. 13 - Suppose polymerase chain reaction (PCR) is used...Ch. 13 - Prob. 17PCh. 13 - A healthy couple with a history of three previous...Ch. 13 - A boy with Down syndrome (trisomy 21) has 46...Ch. 13 - Prob. 20PCh. 13 - 10.28 A small population of deer living on an...Ch. 13 - In humans that XX/XO mosaics, the phenotype is...Ch. 13 - 10.20 A plant breeder would like to develop the...Ch. 13 - In Drosophilia, seven partial deletion (1to7)...Ch. 13 - Two experimental varieties of strawberry are...Ch. 13 - 10.23 In the tomato, Solanum esculentum, tall ()...Ch. 13 - In Drosophila, the wild-type red eye color is...Ch. 13 - A DrosophilaPelement 2.5kb in length is modified...Ch. 13 - A biologist studying flight mechanisms in insects...Ch. 13 - 30. After reading Experimental Insight and...Ch. 13 - 31. Two NotI restriction enzymes cleave DNA on...Ch. 13 - For the following crosses, determine as accurately...
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- What three essential criteria must be met in order to execute asuccessful mapping cross?arrow_forwardTime mapping is performed in a cross involving the genes his, leu, mal, and xyl. The recipient cells were auxotrophic for all four genes. After 25 minutes, mating was interrupted with the following results in recipient cells. Diagram the positions of these genes relative to the origin (O) of the F factor and to one another. (a) 90% were xyl+ (b) 80% were mal+ (c) 20% were his+ (d) none were leu+arrow_forwardExplain the similarities and differences between the procedures used for the coarse-scale mapping and fine-scale mapping of QTLs through controlled crosses, as was accomplished for QTLs involved with tomato size.arrow_forward
- a. draw the relevant plant chromosomes in both plants b. explaint he two different ratiosarrow_forwardIn the Western blot shown here, proteins were isolated from redblood cells and muscle cells from two different individuals. Oneindividual was unaffected, and the other suffered from a diseaseknown as thalassemia, which involves a defect in hemoglobin. Theblot was exposed to an antibody that recognizes β globin, whichis one of the polypeptides that constitute hemoglobin. Equal totalamounts of cellular proteins were added to each lane. Explain these results.arrow_forwardIn an analysis of five rII mutants, complementation testing yielded the following results:arrow_forward
- You are using nitrosoguanidine to “revert” mutant nic-2(nicotinamide-requiring) alleles in Neurospora.You treat cells, plate them on a medium without nicotinamide, and look for prototrophic colonies. You obtainthe following results for two mutant alleles. Explainthese results at the molecular level, and indicate how youwould test your hypotheses.a. With nic-2 allele 1, you obtain no prototrophs at all.b. With nic-2 allele 2, you obtain three prototrophiccolonies A, B, and C, and you cross each separately with awild-type strain. From the cross prototroph A × wildtype, you obtain 100 progeny, all of which are prototrophic.From the cross prototroph B × wild type, you obtain100 progeny, of which 78 are prototrophic and 22 arenicotinamide requiring. From the cross prototrophC × wild type, you obtain 1000 progeny, of which 996 areprototrophic and 4 are nicotinamide requiring.arrow_forwardIn the genotype presented (genomic plus plasmid genes), which of the following statements Is phenotype? genome: IS P O`z+Y° plasmid: I* Pt otzY+ no production of either B-gal and permease O B-gal and permease induced when lactose is present no B-gal is produced and expression of permease when lactose is present constitutive expression of B-gal and permease constitutive expression of B-gal and no expression of permeasearrow_forwardComplementation tests of distinct recessive mutants, 1 through 8, produce the data in the matrix below. A plus (+) indicates complementation, meaning the phenotype of the combined alleles is wild type, and a minus (-) indicates a failure to complement meaning that a mutant phenotype results. Assume that the missing mutant combinations would yield data consistent with the entries that are shown. How many complementation groups are formed by these eight mutants? (Picture attached) A) 2 B) 3 C) 4 D) 5 E) 6arrow_forward
- a. What are the linkage distances between m and r, between r and t, and between m and t?b. Determine the linkage order for the three genes.?c. What is the coefficient of coincidence (see Chapter 4) in this cross? What does it signify?arrow_forwardPlease find the attachmentarrow_forwardIn an imagined transduction experiment with alleles a+, b+,and c+, a+ alone was transduced into an auxotroph 800 times, b+ alone 1200 times, and c+ alone 1500 times. Genes a+ and b+ were both found 3 times, b+ and c+ 12 times, and a+ and c+ one time. What can you conclude regarding the linkage of the three alleles (which is two are closer together). Help me please i will ratearrow_forward
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