In the tomato, Solanumesculentum, tall (
Progeny |
Number |
Tall, smooth, round |
|
Dwarf, peach, oblate |
|
Tall, smooth, oblate |
|
Dwarf, peach, round |
|
Tall, peach, oblate |
|
Dwarf, smooth, round |
|
Tall, peach, round |
|
Dwarf, smooth, oblate |
|
|
Want to see the full answer?
Check out a sample textbook solutionChapter 13 Solutions
Genetic Analysis: An Integrated Approach (2nd Edition)
Additional Science Textbook Solutions
Human Physiology
Essentials of Genetics (9th Edition) - Standalone book
Concepts of Biology
LooseLeaf for Integrated Principles of Zoology
Biology Illinois Edition (Glencoe Science)
- In DrosophilaI, yellow body (y), crossveinless (cv), and forked bristles (f) are all found in the X chromosome, in that order. Yellow is 14 map units from crossveinless, and crossveinlessis 32 map units from forked. A yellow, forked female is crossed to a crossveinless male. An F1 female is crossed to a yelow, crossveinless, forked male, yielding the F2 generation. In the F2, what is the probability of obtaining progeny that express crossveinless and forked, but not yellow? Assume a coefficient of coincidence of 1. In the F2, what is the probability of obtaining progeny that are completely wild type? In the F2, what is the probability of obtaining progeny that express crossveinless, but not yellow or forked?arrow_forwardIn rice, male sterility is controlled by maternal cytoplasmic elements. This phenotype renders the male part of rice plants (i.e. the stamen) unable to produce fertile pollen; the female parts, however, remain receptive to pollination by pollen from male fertile rice plants. However, the presence of a nuclear fertility restorer gene F restores fertility to male-sterile lines. Give the result(s) of the cross and explain the phenotype of the offspring.arrow_forwardThe genotype of a Drosophila with a heterozygous translocation between chromosome 2 and chromosome 3 is shown below, where bw = brown eyes and e = ebony body: bw+ bw e Assume there is no crossing over in the female and that alternate = adjacent 1 = adjacent 2 disjunction. [Yes, these assumptions are incorrect, but they make the problem much easier!] Two individuals of the above genotype, i.e. both heterozygous for this 2;3 translocation and both heterozygous for bw (on chromosome 2) and e (on chromosome 3) are crossed. A (Only zygotes with balanced genomes will survive to adulthood. What proportion of F1 zygotes have a balanced genome? B. Draw the genotype(s) and state the phenotype(s) of the surviving progeny you mentioned in part A above. For each different genotype/phenotype indicate it's frequency among the surviving progeny.arrow_forward
- In corn, the genes v (virescent seedlings), pr (red aleurone), and bm (brown midrib) are all on chromosome 5, but not necessarily in the order given. The cross: v+ pr bm/ v pr+ bm+ with v pr bm/ v pr bm produces 1000 progeny with the following phenotypes: v+ pr bm 226 v pr+ bm+ 229 v+ pr bm+ 153 v pr+ bm 185 v+ pr+ bm 59 v pr bm+ 71 v+ pr+ bm+ 36 v pr bm 41 What is the gene order, and the (b) genetic map of these three genes?arrow_forwardIn Drosophila,, the curled mutation (cu, chromosome 3, position 50.0) results in wings that curl up, while ebony (e, chromosome 3, position 70.7) results in a dark body. True breeding, wild type females are mated with true breeding males with curled wings and ebony bodies. Considering Drosophila notation, which of the following correctly diagrams the P1 cross? X X ++ e + + + O+ X + X + ■ + X + + + 3+ X X X X + + Y Y cu cu cu + cu cu J e e e e e (D e + cu cu (Darrow_forwardMale Drosophila from a true-breeding wild-type stock were irradiated with X-rays and then mated with females from a true-breeding stock carrying the following recessive mutations on the X chromosome: yellow body (y), crossveinless wings (cv), cut wings (ct), singed bristles (sn), and miniature wings (m). These markers are known to map in the order: Recessive alleles: y, cv, ct, sn, m Dominant alleles: y+, cv+, ct+, sn+, m+ y-cv-ct-sn-m у CV ct sn m X-rays х х X ct sn CV у m y+ CV+ ct+ sn+ m+ х X ? Exceptional female: Most of the female progeny of this cross were phenotypically wild type, but one female exhibited ct and sn mutant characteristics. When this exceptional ct sn female was mated with a male from the true-breeding wild-type stock, twice as many females as males appeared among the progeny. a. What is the nature of the X-ray-induced mutation present in the exceptional female? b. Draw the X chromosomes present in the exceptional ct sn female as they would appear during pairing…arrow_forward
- Waxy endosperm (wx), virescent seedling (v), and shrunken endosperm (sh) are all recessive mutants in corn. Waxy and shrunken are both on chromosome IX, located 18 map units apart. Virescent is on chromosome V and is not linked to the other loci. A strain of corn that is homozygous for waxy and virescent is crossed to a strain that is homozygous for shrunken endosperm. The F1 were entirely wild type. An F1 individual was then test crossed to a strain that is homozygous for waxy, virescent, and shrunken. Of 1,000 offspring, how many of the offspring will be virescent and shrunken, but not waxy? Using the information from Problem 1, how many of the offspring will be waxy, virescent, and shrunken?arrow_forwardFemale Drosophila heterozygous for three recessive mutations e (ebony body), st (scarlet eyes), and ss (spineless bristles) were testcrossed, and the following progeny were obtained: Phenotype Number wild-type 67 ebony 8 ebony, scarlet 68 ebony, spineless 347 ebony, scarlet, spineless 78 scarlet 368 scarlet, spineless 10 spineless 54 (a) What indicates that the genes are linked? (b) What was the genotype of the original heterozygous females? (c) What is the order of the genes? (d) What is the map distance between e and st? (e) Between e and ss? (f) What is the coefficient of coincidence? (g) Diagram the crosses in this experiment.arrow_forwardIn D. melanogaster, reduced bristles (rd), cinnabar eyes (cn), and vestigial wings (vg) are recessive traits located on chromosome II in that order. The distance between rd and cn is 7 cM and the distance between cn and vg is 9 cM. The CoC for this chromosome is 0.9. A true-breeding female expressing cinnabar eyes and vestigial wings is crossed to a true-breeding male expressing reduced bristles. The F1 are wild type. An F1 female is then test crossed to a male expressing all three traits. Among the F2 progeny, how often would you expect to observe flies expressing only cinnabar eyes? Using the same information from above, among the F2 progeny, how often would you expect to observe flies expressing only vestigial wings?arrow_forward
- -34m,u, +- See 22mu ->CUE 12mue In Dropsophila, sepia eyes (se), curled wings (cu), and ebony body (e) are found, in this order, on chromosome 3. Sepia is 22 map units from curled, which is 12 map units from ebony. A true-breeding female with sepia eyes and ebony body is crossed to a true- breeding male who has curled wings. The resulting F1 progeny from this cross are all wild type. An F1 female is test crossed to a male expressing all three traits. Assuming a 9. coefficient of coincidence of 1: a. What proportion of the F2 progeny will express only the sepia trait? b. If there are 1000 total progeny, what number will express curved only?arrow_forwardIn the model plant Arabidopsis thaliana, the following alleles were used in a cross: T = presence of trichomes t = absence of trichomes D = tall plants d = dwarf plants W = waxy cuticle w = nonwaxy A = presence of purple anthocyanin pigment a = absence (white) The T/t and D/d loci are linked 26 m.u. apart on chromosome 1, whereas the W/w and A/a loci are linked 8 m.u. apart on chromosome 2. A pure-breeding double-homozygous recessive trichomeless nonwaxy plant is crossed with another pure-breeding double-homozygous recessive dwarf white plant. a. What will be the appearance of the F1? b. Sketch the chromosomes 1 and 2 of the parents and the F1, showing the arrangement of the alleles.c. If the F1 is testcrossed, what proportion of the progeny will have all four recessive phenotypes?arrow_forwardIn Drosophila, the genes st (scarlet eyes), ss (spineless bris- tles), and e (ebony body) are located on chromosome 3, with map positions as indicated: st SS e 44 58 70 Each of these mutations is recessive to its wild-type allele (st*, dark red eyes; ss*, smooth bristles; e*, gray body). Phenotypically wild-type females with the genotype st ss e*/st* st* ss+ e were crossed with triply recessive males. Predict the phenotypes of the progeny and the frequen- cies with which they will occur assuming (a) no interfer- ence and (b) complete interference.arrow_forward
- Human Anatomy & Physiology (11th Edition)BiologyISBN:9780134580999Author:Elaine N. Marieb, Katja N. HoehnPublisher:PEARSONBiology 2eBiologyISBN:9781947172517Author:Matthew Douglas, Jung Choi, Mary Ann ClarkPublisher:OpenStaxAnatomy & PhysiologyBiologyISBN:9781259398629Author:McKinley, Michael P., O'loughlin, Valerie Dean, Bidle, Theresa StouterPublisher:Mcgraw Hill Education,
- Molecular Biology of the Cell (Sixth Edition)BiologyISBN:9780815344322Author:Bruce Alberts, Alexander D. Johnson, Julian Lewis, David Morgan, Martin Raff, Keith Roberts, Peter WalterPublisher:W. W. Norton & CompanyLaboratory Manual For Human Anatomy & PhysiologyBiologyISBN:9781260159363Author:Martin, Terry R., Prentice-craver, CynthiaPublisher:McGraw-Hill Publishing Co.Inquiry Into Life (16th Edition)BiologyISBN:9781260231700Author:Sylvia S. Mader, Michael WindelspechtPublisher:McGraw Hill Education