Chapter 13, Problem 13.56AP

a.

Interpretation Introduction

Interpretation:

Structure of compound has to be drawn that has a primary amine and primary alcohol with molecular formula of ${\text{C}}_{\text{4}}{\text{H}}_{\text{11}}\text{NO}$.

Concept Introduction:

Amines are compounds that contains carbon atom bonded to nitrogen in ammonia by replacing one or more hydrogen atoms.  Primary amine is the one, which has only one carbon atom and two hydrogen atoms bonded to the nitrogen atom.  General structure of primary amine is ${\text{RNH}}_{\text{2}}$.  Secondary amine is the one, which has two carbon atoms and one hydrogen atom bonded to the nitrogen atom.  General structure of secondary amine is ${\text{R}}_{\text{2}}\text{NH}$.  Tertiary amine is the one, which has three carbon atoms bonded to the nitrogen atom.  General structure of tertiary amine is ${\text{R}}_{\text{3}}\text{N}$.

Alcohols are compounds that contain hydroxyl group attached to the carbon atom.  Primary alcohol is the one that has hydroxyl group bonded to the carbon atom that contains two hydrogen atoms.  Secondary alcohol is the one that has hydroxyl group bonded to carbon atom that contains only one hydrogen atom.  Tertiary alcohol is the one that has hydroxyl group bonded to carbon atom that does not have any hydrogen atom.

b.

Interpretation Introduction

Interpretation:

Structure of compound has to be drawn that has a secondary amine and secondary alcohol with molecular formula of ${\text{C}}_{\text{4}}{\text{H}}_{\text{11}}\text{NO}$.

Concept Introduction:

Refer part “a.”.

c.

Interpretation Introduction

Interpretation:

Structure of compound has to be drawn that has a primary amine and tertiary alcohol with molecular formula of ${\text{C}}_{\text{4}}{\text{H}}_{\text{11}}\text{NO}$.

Concept Introduction:

Refer part “a.”.