Chapter 12.8, Problem 18PPS

To determine

The missing measure value of the given pairs of similar solids is to be estimated.

  

Answer to Problem 18PPS

The missing measure value of the given pairs of similar solids is $x=0.36cm$ .

Explanation of Solution

Given:

  

  $\begin{array}{l}{V}_1=2250c{m}^3\\ V_2=18c{m}^3\\ L_1=45cm\\ L_2=xcm\end{array}$

Concept Used:

When the pairs of solids are similar the ratio of the dimensions of the solids is same.

Calculation:

Know that:

The given pair of solids is similar, so take the ratio its dimension’s is same. Hence, the missing measure value of $x$ is calculated as:

  $\begin{array}{l}\frac{V_1}{V_2}=\frac{L_1}{L_2}\\ \frac{2250}{18}=\frac{45}{x}\\ x=\frac{45\times 18}{2250}\\ x=0.36cm\end{array}$

Conclusion:

Hence, missing measure value of $x$ is calculated as $x=0.36cm$ .