Chapter 12.4, Problem 2BCYP

To determine

The volume of the cone whose radius and height is $1\frac{1}{2}yd,9yd$ respectively.

Answer to Problem 2BCYP

The volume of the cone is $21.205y{d}^3$

Explanation of Solution

Given:

  $\begin{array}{l}r=1\frac{1}{2}yd=\frac{3}{2}yd\\ h=9yd\end{array}$

Concept Used:

The volume of the cone is given by the following expression:

  $V=\pi r^2\frac{h}{3}$

Where,

Radius of cone: $r$

Height of cone: $h$

Calculation:

The volume of the cone is given by the following expression:

  $V=\pi r^2\frac{h}{3}$

Put the given data in eq.

  $\begin{array}{l}V=\pi r^2\frac{h}{3}\\ V=\pi r^2\frac{h}{3}\\ V=\pi {\left(\frac{3}{2}\right)}^2\frac{9}{3}\\ V=\pi \times \frac{9}{4}\times 3\\ V=21.205y{d}^3\end{array}$

Conclusion:

Hence, the volume of the cone is $21.205y{d}^3$