Chapter 12.7, Problem 3CYP

To determine

To find: the probability that at least one of the chocolates in the box is a white chocolate.

Answer to Problem 3CYP

Sample. .

Explanation of Solution

Given:

Total number of chocolates in the box is 10.

And the percentage of white chocolates is 20%.

Calculation:

According to the question,

Number of white chocolates is $\frac{20}{100}\times 10=2$

So, the number of non-white chocolates is $10-2=8$ .

Now, probability of getting at least one of the chocolates in the box is a white chocolate is:

  $\begin{array}{l}P\left(\ge 1\text{ white chocolates}\right)\\ =1-P\left(<1\text{white chocolates}\right)\\ =1-P\left(0\right)\\ =1-\left[C\left(10,0\right),{\left(0.2\right)}^0{\left(0.8\right)}^0\right]\\ =1-\end{array}$