Chapter 12.2, Problem 9CYU

a)

To determine

To find : What is margin sampling error.

Answer to Problem 9CYU

  $\pm \text{1}\text{.31\%}$

Explanation of Solution

Given Information :

  $29\%$ of surveyed $5284$ people, will watch some of the summer Olympics on television.

Formula Used:

Margin sampling error = $\pm \frac{1}{\sqrt{n}}$

Calculation :

Sampling error margin = $\pm \sqrt{\frac{1}{5824}}=\pm 1.31\%$

b)

To determine

To find : What is likely interval that contains the percentage of the population that will watch the summer Olympics on television ?

Answer to Problem 9CYU

  $27.69$ to $30.31$

Explanation of Solution

Given Information :

Random survey of $5824$ people $29\%$ said, they will watch same summer Olympic on television.

Calculation :

  $29\pm$ margin sampling error.

  $\Rightarrow 29\pm 1.31=27.69$ to $30.31$ .

Interval is $27.69$ to $30.31$ .