Chapter 12.6, Problem 12PPS

To determine

To find :To find the value of $95\%$ confidence interval.

Answer to Problem 12PPS

  $[46.18,47.82]$

Explanation of Solution

Given information :

The given data is $\overline{x}=47,s=45.1$ and $n=200$.

Formula Used:

  $C.I.=\overline{x}\pm 1.96\times \frac{S}{\sqrt{n}}$

Calculation:

C.I. = $47\pm 1.96\times \frac{5.9}{\sqrt{200}}$

  $=46.18,47.82$

As $46.18\le \mu \le 47.82$

So interval = $[46.18,47.82]$