Chapter 12.4, Problem 47STP

To determine

To solve :The given equation.

Answer to Problem 47STP

  $\text{b}=3$

Explanation of Solution

Given information :

The given equation is ${\log }_{b}9=2$

Formula Used:

  $a^{{\log }_{a}x}=x$

Calculation:

  $\begin{array}{l}{b}^{{\log }_{b}9}=b^2\\ b^2=9\\ \Rightarrow b=\pm 3\end{array}$

  $b=-3$ is rejected as base of log is to be positive.

So, $b=3$