Chapter 12.7, Problem 33PPS

To determine

To find :The value of most likely number of success.

Answer to Problem 33PPS

  $\text{6}\text{.75}$

Explanation of Solution

Given information :

Each binomial distribution has $n$ trials and $p$ is probability of success.

  $n=9,p=0.75$

Calculation:

Expected value, $E(x)=ns,$

Where $n$ is number of trials and $s$ is probability of success.

  $\text{E}(\text{x})=9(0.75)=6.75$