Level curves Consider the upper half of the ellipsoid f ( x , y ) = 1 − x 2 4 − y 2 16 and the point P on the given level curve of f. Compute the slope of the line tangent to the level curve at P and verify that the tangent line is orthogonal to the gradient at that point. 48. f ( x , y ) = 1 / 2 ; P ( 2 , 0 )
Level curves Consider the upper half of the ellipsoid f ( x , y ) = 1 − x 2 4 − y 2 16 and the point P on the given level curve of f. Compute the slope of the line tangent to the level curve at P and verify that the tangent line is orthogonal to the gradient at that point. 48. f ( x , y ) = 1 / 2 ; P ( 2 , 0 )
Solution Summary: The author explains that the slope of the tangent line to the level curve of f(x,y)=sqrt1-x24
Level curvesConsider the upper half of the ellipsoid
f
(
x
,
y
)
=
1
−
x
2
4
−
y
2
16
and the point P on the given level curve of f. Compute the slope of the line tangent to the level curve at P and verify that the tangent line is orthogonal to the gradient at that point.
4. Use method of separation of variable to solve the following wave equation
მłu
J²u
subject to
u(0,t) =0, for t> 0,
u(л,t) = 0, for t> 0,
=
t> 0,
at²
ax²'
u(x, 0) = 0,
0.01 x,
ut(x, 0) =
Π
0.01 (π-x),
0
Solve the following heat equation by method of separation variables:
ди
=
at
subject to
u(0,t) =0, for
-16024
ძx2 •
t>0, 0 0,
ux (4,t) = 0, for
t> 0,
u(x, 0) =
(x-3,
\-1,
0 < x ≤2
2≤ x ≤ 4.
ex
5.
important aspects.
Graph f(x)=lnx. Be sure to make your graph big enough to easily read (use the space given.) Label all
6
33
Chapter 12 Solutions
Student Solutions Manual, Single Variable for Calculus: Early Transcendentals
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, calculus and related others by exploring similar questions and additional content below.