Direction of steepest ascent and descent Consider the following functions and points P a. Find the unit vectors that give the direction of steepest ascent and steepest descent at P. b. Find a vector that points in a direction of no change in the function at P. 28 f ( x , y ) = x 2 + 4 x y − y 2 ; P ( 2 , 1 )
Direction of steepest ascent and descent Consider the following functions and points P a. Find the unit vectors that give the direction of steepest ascent and steepest descent at P. b. Find a vector that points in a direction of no change in the function at P. 28 f ( x , y ) = x 2 + 4 x y − y 2 ; P ( 2 , 1 )
Solution Summary: The author calculates the gradient vector of f(x,y)=x2+4xy-y
Direction of steepest ascent and descentConsider the following functions and points P
a.Find the unit vectors that give the direction of steepest ascent and steepest descent at P.
b.Find a vector that points in a direction of no change in the function at P.
28
f
(
x
,
y
)
=
x
2
+
4
x
y
−
y
2
;
P
(
2
,
1
)
Quantities that have magnitude and direction but not position. Some examples of vectors are velocity, displacement, acceleration, and force. They are sometimes called Euclidean or spatial vectors.
Determine whether the lines
L₁ (t) = (-2,3, −1)t + (0,2,-3) and
L2 p(s) = (2, −3, 1)s + (-10, 17, -8)
intersect. If they do, find the point of intersection.
Convert the line given by the parametric equations y(t)
Enter the symmetric equations in alphabetic order.
(x(t)
= -4+6t
= 3-t
(z(t)
=
5-7t
to symmetric equations.
Find the point at which the line (t) = (4, -5,-4)+t(-2, -1,5) intersects the xy plane.
Chapter 12 Solutions
Student Solutions Manual, Single Variable for Calculus: Early Transcendentals
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