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In Problems 1-22, use the Principle of Mathematical Induction to show that the given statement is true for all natural numbers .
is divisible by 6.
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To prove: The given statement is divisible by 6 is true for all natural numbers using the Principle of Mathematical Induction.
Answer to Problem 22AYU
As the statement is true for the natural number terms, hence the statement is true for all natural numbers.
Explanation of Solution
Given:
Statements says the series is divisible by 6 is true for all natural number.
Formula used:
The Principle of Mathematical Induction
Suppose that the following two conditions are satisfied with regard to a statement about natural numbers:
CONDITION I: The statement is true for the natural number 1.
CONDITION II: If the statement is true for some natural number , it is also true for the next natural number . Then the statement is true for all natural numbers.
Proof:
Consider the statement
is divisible by 6 -----(1)
Step 1: Show that statement (1) is true for the natural number .
That is is divisible by 6. Hence the statement is true for the natural number .
Step 2: Assume that the statement is true for some natural number .
That is is divisible by 6 -----(2)
Step 3: Prove that the statement is true for the next natural number .
That is, to prove that is divisible by 2
Consider
From equation (2), first term in the above equation is divisible by 6 and second term is a multiple of three and product of two consecutive integers.
It is a known fact that the product of two consecutive integers is even. So the consecutive integers is even that is it’s a multiple of 2.
The product of multiple of 3 and multiple of 2 is the multiple of 6. Therefore the second term is divisible by 6.
Hence is divisible by 6.
As the statement is true for the natural number terms, hence the statement is true for all natural numbers.
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Precalculus Enhanced with Graphing Utilities
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