
Concept explainers
In Problems 31-38, find the first term and the common difference of the arithmetic sequence described. Give a recursive formula for the sequence. Find a formula for the nth term.

To find: The term, common difference, recursive formula and formula for th term.
Answer to Problem 29AYU
1.
2.
3.
Explanation of Solution
Given:
term is 8 and term is 44.
Formula used:
Formula for nth term:
Calculation:
From Eq (1) and given data,
Solving above two equations,
;
From Eq(2), we get the recursive formula,
The formula for term is
Chapter 12 Solutions
Precalculus Enhanced with Graphing Utilities
Additional Math Textbook Solutions
Elementary Statistics
University Calculus: Early Transcendentals (4th Edition)
Elementary Statistics (13th Edition)
Basic Business Statistics, Student Value Edition
Thinking Mathematically (6th Edition)
Calculus: Early Transcendentals (2nd Edition)
- Solve please thanks!arrow_forwardSolve please and thank youarrow_forwardAccording to Newton's law of universal gravitation, the force F between two bodies of constant mass GmM m and M is given by the formula F = , where G is the gravitational constant and d is the d² distance between the bodies. a. Suppose that G, m, and M are constants. Find the rate of change of force F with respect to distance d. F' (d) 2GmM b. Find the rate of change of force F with gravitational constant G = 6.67 × 10-¹¹ Nm²/kg², on two bodies 5 meters apart, each with a mass of 250 kilograms. Answer in scientific notation, rounding to 2 decimal places. -6.67x10 N/m syntax incomplete.arrow_forward
- Solve please and thank youarrow_forwardmv2 The centripetal force of an object of mass m is given by F (r) = rotation and r is the distance from the center of rotation. ' where v is the speed of r a. Find the rate of change of centripetal force with respect to the distance from the center of rotation. F(r) b. Find the rate of change of centripetal force of an object with mass 500 kilograms, velocity of 13.86 m/s, and a distance from the center of rotation of 300 meters. Round to 2 decimal places. N/m (or kg/s²) F' (300)arrow_forwardSolve work shown please and thanks!arrow_forward
- Given the following graph of the function y = f(x) and n = = 6, answer the following questions about the area under the curve from x graph to enlarge it.) 1 (Round your answer to within two decimal places if necessary, but do not round until your final computation.) a. Use the Trapezoidal Rule to estimate the area. Estimate: T6 G b. Use Simpson's Rule to estimate the area. Estimate: S6 - ID = 0 to x = 6. (Click on aarrow_forward"Solve the following differential equation using the Operator Method and the Determinant Method:" Solve by dr no ai """'+3y"" + 3y+y=arrow_forward(4,4) M -4 2 2 -4 (-4,-4) 4 8 10 12 (8,-4) (12,-4) Graph of f The figure shows the graph of a piecewise-linear function f. For −4≤x≤12, the function g is x defined by g(x) = √ƒ (t)dt . . Find the value of g(6). Find the value of g'(6). |arrow_forward
- PREVIOUS ANSWERS ASK YOUR TEACHER PRACTICE ANOTHER Find the derivative of the function. f'(x) = X x + √3x f(x) = 3x-5 (3√√3x+11√√x+5√3 2√√x (3x-5)² Need Help? Read It SUBMIT ANSWERarrow_forwardPREVIOUS ANSWERS ASK YOUR TEACHER PRACTICE A Find the derivative of the function and evaluate f'(x) at the given val f(x) = (√√√x + 3x) (x3/2 - x); x = 1 f'(x) = 9x 412 (12x (13) 2 - 4x-3√√√x f'(1) = 2 Need Help? Read It Watch It SUBMIT ANSWERarrow_forwardConsider the following functions. g(x) = x + √3x h(x) = 3x-5 x + √3x f(x) = = 3x-5 Find the derivative of each function. g'(x) h'(x) = = f'(x) = 3 = +1 2√3x 3 (3√3x + 10√√x +5√√√3 2√√x (3x-5)² Need Help? Read It SUBMIT ANSWERarrow_forward
- Calculus: Early TranscendentalsCalculusISBN:9781285741550Author:James StewartPublisher:Cengage LearningThomas' Calculus (14th Edition)CalculusISBN:9780134438986Author:Joel R. Hass, Christopher E. Heil, Maurice D. WeirPublisher:PEARSONCalculus: Early Transcendentals (3rd Edition)CalculusISBN:9780134763644Author:William L. Briggs, Lyle Cochran, Bernard Gillett, Eric SchulzPublisher:PEARSON
- Calculus: Early TranscendentalsCalculusISBN:9781319050740Author:Jon Rogawski, Colin Adams, Robert FranzosaPublisher:W. H. FreemanCalculus: Early Transcendental FunctionsCalculusISBN:9781337552516Author:Ron Larson, Bruce H. EdwardsPublisher:Cengage Learning





