
Concept explainers
To find: The fifth term and

Answer to Problem 24AYU
The fifth term of the geometric sequence is
Explanation of Solution
Given information:
The first term
Calculation:
The formula for nth term of geometric sequence is given by,
Calculate the fifth term.
Calculate the
Therefore, the fifth term of the geometric sequence is
Chapter 12 Solutions
Precalculus Enhanced with Graphing Utilities
Additional Math Textbook Solutions
University Calculus: Early Transcendentals (4th Edition)
Thinking Mathematically (6th Edition)
Algebra and Trigonometry (6th Edition)
A Problem Solving Approach To Mathematics For Elementary School Teachers (13th Edition)
Introductory Statistics
Elementary Statistics (13th Edition)
- i need help pleasearrow_forward(#1) Consider the solid bounded below by z = x² and above by z = 4-y². If we were to project this solid down onto the xy-plane, you should be able to use algebra to determine the 2D region R in the xy-plane for the purposes of integration. Which ONE of these limite of integration would correctly describe R? (a) y: x24x: -22 - (b) y: 22 x: 04-y² (c) y: -√√4-x2. →√√4x²x: −2 → 2 (d) z: 24-y² y: -2 → 2 (e) None of the abovearrow_forwardX MindTap - Cenxxxx Answered: tat "X A 26308049 X 10 EKU-- SP 25: X E DNA Sequenc X b/ui/evo/index.html?elSBN=9780357038406&id=339416021&snapshotid=877369& GE MINDTAP , Limits, and the Derivative 40. Answer 5 4-5 t-10 5 f(x) = 2x - 4 if x ≤0 if x 0 10 ++ -4-3-2-1 f(x) = MacBook Pro Search or type URL 5 1234 x² +1 if x = 0 if x = 0 +arrow_forward
- MindTap - Cemy X Answered: tat x A 26308049 × 10 EKU--SP 25:11 × E DNA Sequence x H. pylori index.html?elSBN=9780357038406&id=339416021&snapshotid=877369& NDTAP and the Derivative 41. 42. Answer 12 Ay 5 + -10-5 5 10 -5- f(x) = x +5 if x ≤ 0 -x²+5 if x > 0 to -5 5. 5 f(x) = |x − 1| MacBook Pro AAarrow_forwardMind Tap - Cenxxx Answered: tat X A 26308049 × 10 EKU-- SP 25: X E DNA Sequence x H. pylor vo/index.html?elSBN=9780357038406&id=339416021&snapshotld=877369& MINDTAP its, and the Derivative 44. Answer 5 X -10-5 5 10 -5. f(x) = 2 + x +5 if x 0 3 4 f(x) = x² - 1 x+1 if x = -1 MacBook Pro G Search or type URL if x = -1 + AA aarrow_forwardCalculus lll May I please have an explanation of the multivariable chain rule in the example given? Thank youarrow_forward
- Mind Tap - Cenxxx Answered: tat X A 26308049 X 10 EKU-- SP 25:1 x E DNA Sequence x H. pyl /nb/ui/evo/index.html?elSBN 9780357038406&id=339416021&snapshotid=877369& ⭑ SAGE MINDTAP a ons, Limits, and the Derivative 吃 AA In Exercises 45, 46, 47, 48, 49, 50, 51, 52, 53, 54, 55, and 56, find the values of x for which each function is continuous. 45. f(x) = 2x²+x-1 Answer▾ 46. f(x) = x³- 2x²+x-1 47. f(x) 2 = x²+1 Answer 48. f(x) = 49. f(x) = Answer 50. f(x) = 51. f(x) = I 2x²+1 2 2x - 1 x+1 x-1 2x + 1 x²+x-2 Answer↓ 52. f(x)= = x-1 x2+2x-3 53. $ % MacBook Proarrow_forward37. lim f (x) and lim f (x), where x+0+ x 0 Answer -> 38. lim f (x) and lim f (x), where +0x x―0M 2x if x 0arrow_forward37. lim f (x) and lim f (x), where x+0+ x 0 Answer -> 38. lim f (x) and lim f (x), where +0x x―0M 2x if x 0arrow_forward
- Apply the Chain Rulearrow_forwardCalculus lll May I please have the solution for the following exercise? Thank youarrow_forward2z = el+cos(x+y) 24 = olt etz dy = 1 dt dz e²² + cos (+²+1++). 2++ (1+++cos C+²+1++) (+) dz 2+. etz 2t, + 2+⋅ cos (t² +++ 1) + t (1++1 dt + cos (+²+++1) 2. W= (yz) (yz) x x=e8++ 2 y= 3² + 3st, z=sent, hallar 2w 2w د 2u 2t 25 2t AX119 S Narrow_forward
- Calculus: Early TranscendentalsCalculusISBN:9781285741550Author:James StewartPublisher:Cengage LearningThomas' Calculus (14th Edition)CalculusISBN:9780134438986Author:Joel R. Hass, Christopher E. Heil, Maurice D. WeirPublisher:PEARSONCalculus: Early Transcendentals (3rd Edition)CalculusISBN:9780134763644Author:William L. Briggs, Lyle Cochran, Bernard Gillett, Eric SchulzPublisher:PEARSON
- Calculus: Early TranscendentalsCalculusISBN:9781319050740Author:Jon Rogawski, Colin Adams, Robert FranzosaPublisher:W. H. FreemanCalculus: Early Transcendental FunctionsCalculusISBN:9781337552516Author:Ron Larson, Bruce H. EdwardsPublisher:Cengage Learning





