Chapter 12.1, Problem 8P

Find each sum or difference.

$\left[\begin{array}{l}0.1-32.3\\ 01.2-1\\ 33.5-2.6\end{array}\right]-\left[\begin{array}{l}3.20-2\\ 4.78-8\\ 3.4-26.1\end{array}\right]$

To determine

Find the sum or the difference.

Answer to Problem 8P

  $\left[\begin{array}{l}\text{-3}\text{.1 -3 4}\text{.3}\\ \text{-4}\text{.7 -6}\text{.8 7}\\ \text{-0}\text{.4 5}\text{.5 -8}\text{.7}\end{array}\right]$

Explanation of Solution

Given:

  $\left[\begin{array}{l}\text{0}\text{.1 -3 2}\text{.3}\\ \text{0 1}\text{.2 -1}\\ \text{3 3}\text{.5 -2}\text{.6}\end{array}\right]-\left[\begin{array}{l}\text{3}\text{.2 0 -2}\\ \text{4}\text{.7 8 -8}\\ \text{3}\text{.4 -2 6}\text{.1}\end{array}\right]$

Formula Used:

  $\left[\begin{array}{l}\text{a b c}\\ \text{d e f}\\ \text{g h i}\end{array}\right]-\left[\begin{array}{l}\text{j k l}\\ \text{m n o}\\ \text{p q r}\end{array}\right]=\left[\begin{array}{l}\text{a-j b-k c-l}\\ \text{d-m e-n f-o}\\ \text{g-p h-q i-r}\end{array}\right]$

Calculation:

  $\left[\begin{array}{l}\text{0}\text{.1 -3 2}\text{.3}\\ \text{0 1}\text{.2 -1}\\ \text{3 3}\text{.5 -2}\text{.6}\end{array}\right]-\left[\begin{array}{l}\text{3}\text{.2 0 -2}\\ \text{4}\text{.7 8 -8}\\ \text{3}\text{.4 -2 6}\text{.1}\end{array}\right]=\left[\begin{array}{l}\text{0}\text{.1-3}\text{.2 -3-0 2}\text{.3+2}\\ \text{0-4}\text{.7 1}\text{.2-8 -1+8}\\ \text{3-3}\text{.4 3}\text{.5+2 -2}\text{.6-6}\text{.1}\end{array}\right]=\left[\begin{array}{l}\text{-3}\text{.1 -3 4}\text{.3}\\ \text{-4}\text{.7 -6}\text{.8 7}\\ \text{-0}\text{.4 5}\text{.5 -8}\text{.7}\end{array}\right]$