Chapter 12.1, Problem 7P

Find each sum or difference.

$\left[\begin{array}{l}0.1-32.3\\ 01.2-1\\ 33.5-2.6\end{array}\right]+\left[\begin{array}{l}3.20-2\\ 4.78-8\\ 3.4-26.1\end{array}\right]$

To determine

Find the sum or the difference.

Answer to Problem 7P

  $\left[\begin{array}{l}\text{3}\text{.3 -3 0}\text{.3}\\ \text{4}\text{.7 9}\text{.2 -9}\\ \text{6}\text{.4 1}\text{.5 3}\text{.5}\end{array}\right]$

Explanation of Solution

Given:

  $\left[\begin{array}{l}\text{0}\text{.1 -3 2}\text{.3}\\ \text{0 1}\text{.2 -1}\\ \text{3 3}\text{.5 -2}\text{.6}\end{array}\right]+\left[\begin{array}{l}\text{3}\text{.2 0 -2}\\ \text{4}\text{.7 8 -8}\\ \text{3}\text{.4 -2 6}\text{.1}\end{array}\right]$

Formula Used:

  $\left[\begin{array}{l}\text{a b c}\\ \text{d e f}\\ \text{g h i}\end{array}\right]+\left[\begin{array}{l}\text{j k l}\\ \text{m n o}\\ \text{p q r}\end{array}\right]=\left[\begin{array}{l}\text{a+j b+k c+l}\\ \text{d+m e+n f+o}\\ \text{g+p h+q i+r}\end{array}\right]$

Calculation:

  $\left[\begin{array}{l}\text{0}\text{.1 -3 2}\text{.3}\\ \text{0 1}\text{.2 -1}\\ \text{3 3}\text{.5 -2}\text{.6}\end{array}\right]+\left[\begin{array}{l}\text{3}\text{.2 0 -2}\\ \text{4}\text{.7 8 -8}\\ \text{3}\text{.4 -2 6}\text{.1}\end{array}\right]=\left[\begin{array}{l}\text{0}\text{.1+3}\text{.2 -3+0 2}\text{.3-2}\\ \text{0+4}\text{.7 1}\text{.2+8 -1-8}\\ \text{3+3}\text{.4 3}\text{.5-2 -2}\text{.6+6}\text{.1}\end{array}\right]=\left[\begin{array}{l}\text{3}\text{.3 -3 0}\text{.3}\\ \text{4}\text{.7 9}\text{.2 -9}\\ \text{6}\text{.4 1}\text{.5 3}\text{.5}\end{array}\right]$