Chapter 12.8, Problem 19P

The probability that Bob will make a free throw is $\frac{2}{5}$.

What is the probability that Bob will make his next two free throws?

To determine

Find the probability that B will make his next two free throws

Answer to Problem 19P

  $\frac{4}{25}$

Explanation of Solution

Given:

The probability that B will make a free throw is $\frac{2}{5}$ .

Formula Used:

  $P(E)=\frac{\text{Favourable outcomes of E}}{\text{total number of outcomes}}$

  $P\left(AandB\right)=P\left(A\right)\cdot P\left(B\right)$ ; if A and B are independent events.

Calculation:

Since the events of throw are independent. So, next throw does not depend on previous one .

So, consecutive throws are independent events.

So, the probability of making two consecutive free throws = $\frac{2}{5}\cdot \frac{2}{5}=\frac{4}{25}$