OR 16 f(x) = Ef 16 χ по x²-2 410 | y = (x+2) + 4 Y-INT: y = 0 X-INT: X=0 VA: x=2 OA: y=x+2 0 X-INT: X=-2 X-INT: y = 2 VA 0 2 whole. 2-2 4 y - (x+2) = 27-270 + xxx> 2 क् above OA (x+2) OA x-2/x²+0x+0 2 x-2x 2x+O 2x-4 4 X<-1000 4/4/2<0 below Of y VA X=2 X-2 OA y=x+2 -2 2 (0,0) 2 χ

Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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OR
16 f(x) =
Ef 16
χ
по
x²-2 410 | y = (x+2) + 4
Y-INT: y = 0
X-INT: X=0
VA: x=2
OA: y=x+2
0
X-INT: X=-2
X-INT: y = 2
VA
0
2
whole.
2-2
4
y - (x+2) = 27-270
+
xxx> 2
क्
above OA
(x+2) OA
x-2/x²+0x+0
2
x-2x
2x+O
2x-4
4
X<-1000 4/4/2<0 below Of
y
VA
X=2
X-2
OA
y=x+2
-2
2
(0,0)
2
χ
Transcribed Image Text:OR 16 f(x) = Ef 16 χ по x²-2 410 | y = (x+2) + 4 Y-INT: y = 0 X-INT: X=0 VA: x=2 OA: y=x+2 0 X-INT: X=-2 X-INT: y = 2 VA 0 2 whole. 2-2 4 y - (x+2) = 27-270 + xxx> 2 क् above OA (x+2) OA x-2/x²+0x+0 2 x-2x 2x+O 2x-4 4 X<-1000 4/4/2<0 below Of y VA X=2 X-2 OA y=x+2 -2 2 (0,0) 2 χ
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