Introductory Chemistry: An Active Learning Approach
6th Edition
ISBN: 9781305079250
Author: Mark S. Cracolice, Ed Peters
Publisher: Cengage Learning
expand_more
expand_more
format_list_bulleted
Concept explainers
Question
Chapter 12, Problem 43E
Interpretation Introduction
Interpretation:
The reason as to why ionic bonds are called electron-transfer bonds and covalent bonds are known as electron-sharing bonds is to be stated.
Concept introduction:
The sharing of electrons between atoms forms a covalent bond. An ionic bond is formed by the transferring or accepting of electrons from the valence shell. In an ionic bond, atoms are firmly held by the electrostatic force of attraction. Covalent bonds are stronger than ionic bonds.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionStudents have asked these similar questions
reaction scheme for C39H4202
Hydrogenation of Alkyne (Alkyne to
Alkene)
show reaction (drawing) please
Give detailed mechanism Solution with explanation needed. Don't give Ai generated solution
Show work with explanation needed....don't give Ai generated solution
Chapter 12 Solutions
Introductory Chemistry: An Active Learning Approach
Ch. 12 - Write the electronic configuration for the ions of...Ch. 12 - A monoatomic ion with a charge of 1 has an...Ch. 12 - Identify by symbol two positively charged...Ch. 12 - Considering only ions with charges of 1+,2+,1, and...Ch. 12 - Write the symbols of two ions that are...Ch. 12 - Considering only ions with charges of 1+,2+,1, and...Ch. 12 - Prob. 7ECh. 12 - Prob. 8ECh. 12 - When potassium and chlorine react and form an...Ch. 12 - Fill in the blanks with the smallest integers...
Ch. 12 - Prob. 11ECh. 12 - Prob. 12ECh. 12 - Prob. 13ECh. 12 - Prob. 14ECh. 12 - Prob. 15ECh. 12 - Prob. 16ECh. 12 - Prob. 17ECh. 12 - Prob. 18ECh. 12 - Prob. 19ECh. 12 - Prob. 20ECh. 12 - Prob. 21ECh. 12 - Consider the following bonds: GeSe, BrSe, BrGe....Ch. 12 - Prob. 23ECh. 12 - Consider the following bonds: TeSe, OTe, OSe....Ch. 12 - Prob. 25ECh. 12 - Prob. 26ECh. 12 - Prob. 27ECh. 12 - Prob. 28ECh. 12 - Prob. 29ECh. 12 - What is the maximum number of atoms to which a...Ch. 12 - Prob. 31ECh. 12 - Prob. 32ECh. 12 - Prob. 33ECh. 12 - Prob. 34ECh. 12 - Prob. 35ECh. 12 - Prob. 36ECh. 12 - Prob. 37ECh. 12 - Prob. 38ECh. 12 - Prob. 39ECh. 12 - Prob. 40ECh. 12 - Prob. 41ECh. 12 - Prob. 42ECh. 12 - Prob. 43ECh. 12 - Prob. 44ECh. 12 - Prob. 45ECh. 12 - Prob. 46ECh. 12 - Prob. 47ECh. 12 - Prob. 48ECh. 12 - Which orbitals of each atom overlap in forming a...Ch. 12 - Prob. 50ECh. 12 - Prob. 51ECh. 12 - A monatomic ion with a 2 charge has the electron...Ch. 12 - Prob. 53ECh. 12 - Prob. 54ECh. 12 - Prob. 55ECh. 12 - Prob. 56ECh. 12 - Prob. 57ECh. 12 - Prob. 58ECh. 12 - Prob. 59ECh. 12 - Prob. 60ECh. 12 - Prob. 61ECh. 12 - Which ions among the following are isoelectronic...Ch. 12 - Prob. 12.2TCCh. 12 - Prob. 12.3TCCh. 12 - Prob. 12.4TCCh. 12 - Prob. 12.5TCCh. 12 - Prob. 1CLECh. 12 - Prob. 2CLECh. 12 - Prob. 3CLECh. 12 - Prob. 4CLECh. 12 - Prob. 5CLECh. 12 - Prob. 6CLECh. 12 - Write the electron configurations for the oxide...Ch. 12 - Arrange the following bonds in order of decreasing...
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.Similar questions
- Pleasssssseeee solve this question in cheeemsirty, thankss sirarrow_forwardThe Ksp for lead iodide ( Pbl₂) is 1.4 × 10-8. Calculate the solubility of lead iodide in each of the following. a. water Solubility = mol/L b. 0.17 M Pb(NO3)2 Solubility = c. 0.017 M NaI mol/L Solubility = mol/Larrow_forwardPleasssssseeee solve this question in cheeemsirty, thankss sirarrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Introductory Chemistry: An Active Learning Approa...ChemistryISBN:9781305079250Author:Mark S. Cracolice, Ed PetersPublisher:Cengage LearningLiving By Chemistry: First Edition TextbookChemistryISBN:9781559539418Author:Angelica StacyPublisher:MAC HIGHERWorld of Chemistry, 3rd editionChemistryISBN:9781133109655Author:Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCostePublisher:Brooks / Cole / Cengage Learning
- Chemistry: Principles and PracticeChemistryISBN:9780534420123Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward MercerPublisher:Cengage LearningChemistry: Matter and ChangeChemistryISBN:9780078746376Author:Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl WistromPublisher:Glencoe/McGraw-Hill School Pub CoChemistry & Chemical ReactivityChemistryISBN:9781337399074Author:John C. Kotz, Paul M. Treichel, John Townsend, David TreichelPublisher:Cengage Learning
Introductory Chemistry: An Active Learning Approa...
Chemistry
ISBN:9781305079250
Author:Mark S. Cracolice, Ed Peters
Publisher:Cengage Learning
Living By Chemistry: First Edition Textbook
Chemistry
ISBN:9781559539418
Author:Angelica Stacy
Publisher:MAC HIGHER
World of Chemistry, 3rd edition
Chemistry
ISBN:9781133109655
Author:Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCoste
Publisher:Brooks / Cole / Cengage Learning
Chemistry: Principles and Practice
Chemistry
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Cengage Learning
Chemistry: Matter and Change
Chemistry
ISBN:9780078746376
Author:Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl Wistrom
Publisher:Glencoe/McGraw-Hill School Pub Co
Chemistry & Chemical Reactivity
Chemistry
ISBN:9781337399074
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:Cengage Learning
Stoichiometry - Chemistry for Massive Creatures: Crash Course Chemistry #6; Author: Crash Course;https://www.youtube.com/watch?v=UL1jmJaUkaQ;License: Standard YouTube License, CC-BY
Bonding (Ionic, Covalent & Metallic) - GCSE Chemistry; Author: Science Shorts;https://www.youtube.com/watch?v=p9MA6Od-zBA;License: Standard YouTube License, CC-BY
General Chemistry 1A. Lecture 12. Two Theories of Bonding.; Author: UCI Open;https://www.youtube.com/watch?v=dLTlL9Z1bh0;License: CC-BY