Lock-and-key analogy has to be explained briefly for the interaction taking place between drugs and receptor sites. Concept Introduction: Drugs: Drugs are molecules which are taken from an external source to change the normal functioning of the body. The action of drug is in molecular level and the design of many drugs are in such a way that it mimics a particular neurotransmitter or hormone. Drugs bind with receptors showing an increased or decreased effect. Receptors: Receptors is a molecule or a part of molecule which interacts with a neurotransmitter, a hormone or other molecules which are biochemically active so that a response is initiated in a target cell.

Question

Want to see the full answer?

Answer 1

Question

Chapter 12, Problem 36Q

Interpretation Introduction

Interpretation:

Lock-and-key analogy has to be explained briefly for the interaction taking place between drugs and receptor sites.

Concept Introduction:

Drugs: Drugs are molecules which are taken from an external source to change the normal functioning of the body. The action of drug is in molecular level and the design of many drugs are in such a way that it mimics a particular neurotransmitter or hormone. Drugs bind with receptors showing an increased or decreased effect.

Receptors: Receptors is a molecule or a part of molecule which interacts with a neurotransmitter, a hormone or other molecules which are biochemically active so that a response is initiated in a target cell.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

Please help with number 6 I got a negative number could that be right?

1,4-Dimethyl-1,3-cyclohexadiene can undergo 1,2- or 1,4-addition with hydrogen halides. (a) 1,2-Addition i. Draw the carbocation intermediate(s) formed during the 1,2-addition of hydrobromic acid to 1,4-dimethyl-1,3-cyclohexadiene. ii. What is the major 1,2-addition product formed during the reaction in (i)? (b) 1,4-Addition i. Draw the carbocation intermediate(s) formed during the 1,4-addition of hydrobromic acid to 1,4-dimethyl-1,3-cyclohexadiene. ii. What is the major 1,4-addition product formed from the reaction in (i)? (c) What is the kinetic product from the reaction of one mole of hydrobromic acid with 1,4-dimethyl-1,3-cyclohexadiene? Explain your reasoning. (d) What is the thermodynamic product from the reaction of one mole of hydrobro-mic acid with 1,4-dimethyl-1,3-cyclohexadiene? Explain your reasoning. (e) What major product will result when 1,4-dimethyl-1,3-cyclohexadiene is treated with one mole of hydrobromic acid at - 78 deg * C ? Explain your reasoning.

Give the product of the bimolecular elimination from each of the isomeric halogenated compounds. Reaction A Reaction B. КОВ CH₂ HotBu +B+ ко HOIBU +Br+ Templates More QQQ Select Cv Templates More Cras QQQ One of these compounds undergoes elimination 50x faster than the other. Which one and why? Reaction A because the conformation needed for elimination places the phenyl groups and to each other Reaction A because the conformation needed for elimination places the phenyl groups gauche to each other. ◇ Reaction B because the conformation needed for elimination places the phenyl groups gach to each other. Reaction B because the conformation needed for elimination places the phenyl groups anti to each other.