
Interpretation:
Whether the phosphofructokinase reaction in muscle is more or less exergonic than under standard conditions should be identified along with its amount.
Concept introduction: The formula used:
Where,
ΔG = calculated Gibbs free energy (change)
ΔGo = standard Gibbs free energy (change)
R = universal gas constant
T = temperature
[ products] = concentration of products
[reactants] concentration of reactants

Explanation of Solution
The phosphofructokinase reaction is as follows:
Thus,
The value of standard Gibbs free energy of the reaction is
The expression for
Putting the values,
It is determined that the phosphofructokinase reaction in muscle is neither less or nor more exergonic instead it is equally energetic in reactions occur under standard conditions as above calculated Gibbs free energy is equal to standard Gibbs free energy.
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Chapter 12 Solutions
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