According to its directional distribution, solar radiation incident on the earth’s surface may be divided into two components. The direct component consists of parallel rays incident at a fixed zenith angle θ , while the diffuse component consists of radiation that may be approximated as being diffusely distributed with θ . Consider clear sky conditions for which the direct radiation is incident at 0 = 30 ∘ , with a total flux (based on an area that is normal to the rays) of q d i r " = 1000 W / m 2 , and the total intensity of the diffuse radiation is I d i f = 70 W / m 2 · s r . What is the total solar irradiation at the earth’ s surface?
According to its directional distribution, solar radiation incident on the earth’s surface may be divided into two components. The direct component consists of parallel rays incident at a fixed zenith angle θ , while the diffuse component consists of radiation that may be approximated as being diffusely distributed with θ . Consider clear sky conditions for which the direct radiation is incident at 0 = 30 ∘ , with a total flux (based on an area that is normal to the rays) of q d i r " = 1000 W / m 2 , and the total intensity of the diffuse radiation is I d i f = 70 W / m 2 · s r . What is the total solar irradiation at the earth’ s surface?
Solution Summary: The author calculates the total solar irradiation at the surface of earth as the sum of direct radiation and diffuse radiation.
According to its directional distribution, solar radiation incident on the earth’s surface may be divided into two components. The direct component consists of parallel rays incident at a fixed zenith angle
θ
, while the diffuse component consists of radiation that may be approximated as being diffusely distributed with
θ
. Consider clear sky conditions for which the direct radiation is incident at
0
=
30
∘
, with a total flux (based on an area that is normal to the rays) of
q
d
i
r
"
=
1000
W
/
m
2
, and the total intensity of the diffuse radiation is
I
d
i
f
=
70
W
/
m
2
·
s
r
. What is the total solar irradiation at the earth’ s surface?
4. Two links made of heat treated 6061 aluminum (Sy = 276 MPa, Sys = 160 MPa) are pinned
together using a steel dowel pin (Sy = 1398 MPa, Sys = 806 MPa) as shown below. The
links are to support a load P with a factor of safety of at least 2.0. Determine if the link will
fail first by tearout, direct shear of the pin, bearing stress on the link, or tensile stress at
section AA. (Hint: find the load P for each case and choose the case that gives the smallest
load.)
P
8 mm
P
8 mm
¡+A
3 mm
→A
10 mm
P
1. For a feature other than a sphere, circularity is where:
A. The axis is a straight line
B. The modifier is specified with a size dimension
C. All points of the surface intersected by any plane
perpendicular to an axis or spine (curved line) are
equidistant from that axis or spine
D. All points of the surface intersected by any plane
passing through a common center are equidistant
from that center
2. What type of variation is limited by a circularity toler-
ance zone?
A. Ovality
B. Tapering
C. Bending
D. Warping
3. How does the Rule #1 boundary affect the application
of a circularity tolerance?
A. The modifier must be used.
B. The feature control frame must be placed next to
the size dimension.
C. The circularity tolerance value must be less than
the limits of size tolerance.
D. Circularity cannot be applied where a Rule #1
boundary exists.
4. A circularity tolerance may use a
modifier.
A. Ø
B. F
C. M
D. ℗
5. A real-world application for a circularity tolerance is:
A. Assembly (i.e.,…
3. A steel bar is pinned to a vertical support column by a 10 mm diameter hardened dowel pin,
Figure 1. For P = 7500 N, find:
a. the shear stress in the pin,
b. the direct bearing stress on the hole in the bar,
c. the minimum value of d to prevent tearout failure if the steel bar has a shear strength of
175 MPa.
support column
pin
bar
thickness of bar = 8 mm
h
d
150 mm
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