Radiation from the atmosphere or sky can be estimated as a fraction of the blackbody radiation corresponding to the air temperature near the ground, T a i r .That is, irradiation from the sky can be expressed as G a t m = ε s k y σ T a i r 4 and for a clear night sky, the emissivity is correlated by an expression of the form ε s k y = 0.741 + 0 .0062T d p , where T d p is the dew point temperature ( c ∘ ) Consider a flat plate exposed to the night sky and in ambient air at 15 ∘ C c with a relative humidity of 70%. Assume the back side of the plate is insulated, and that the convection coefficient on the front side can be estimated by the correlation h ( W / m 2 ⋅ K ) = 1.25 Δ T 1 / 3 , where Δ T is the absolute value of the plate-to-air temperature difference. Will dew form on the plate if the surface is (a) clean and metallic with ε =0 .23 , and (b) painted with ε =0 .85 ?
Radiation from the atmosphere or sky can be estimated as a fraction of the blackbody radiation corresponding to the air temperature near the ground, T a i r .That is, irradiation from the sky can be expressed as G a t m = ε s k y σ T a i r 4 and for a clear night sky, the emissivity is correlated by an expression of the form ε s k y = 0.741 + 0 .0062T d p , where T d p is the dew point temperature ( c ∘ ) Consider a flat plate exposed to the night sky and in ambient air at 15 ∘ C c with a relative humidity of 70%. Assume the back side of the plate is insulated, and that the convection coefficient on the front side can be estimated by the correlation h ( W / m 2 ⋅ K ) = 1.25 Δ T 1 / 3 , where Δ T is the absolute value of the plate-to-air temperature difference. Will dew form on the plate if the surface is (a) clean and metallic with ε =0 .23 , and (b) painted with ε =0 .85 ?
Solution Summary: The author explains the emissivity of the sky, convection coefficient, ambient temperature, relative humidity, and energy balance.
Radiation from the atmosphere or sky can be estimated as a fraction of the blackbody radiation corresponding to the air temperature near the ground,
T
a
i
r
.That is, irradiation from the sky can be expressed as
G
a
t
m
=
ε
s
k
y
σ
T
a
i
r
4
and for a clear night sky, the emissivity is correlated by an expression of the form
ε
s
k
y
=
0.741
+ 0
.0062T
d
p
,
where T
d
p
is the dew point temperature
(
c
∘
)
Consider a flat plate exposed to the night sky and in ambient air at
15
∘
C
c with a relative humidity of 70%. Assume the back side of the plate is insulated, and that the convection coefficient on the front side can be estimated by the correlation
h
(
W
/
m
2
⋅
K
)
=
1.25
Δ
T
1
/
3
, where
Δ
T
is the absolute value of the plate-to-air temperature difference. Will dew form on the plate if the surface is (a) clean and metallic with
ε
=0
.23
, and (b) painted with
ε
=0
.85
?
This is an old practice exam. Fce = 110lb and FBCD = 62 lb but why
Quiz/An eccentrically loaded bracket is welded to the support as shown in Figure below. The load is static. The weld size
for weld w1 is h1 = 4mm, for w2 h2 = 6mm, and for w3 is h3 =6.5 mm. Determine the safety factor (S.f) for the welds.
F=29 kN. Use an AWS Electrode type (E100xx).
163 mm
S
133 mm
140 mm
Please solve the question above
I solved the question but I'm sure the answer is wrong
the link :
https://drive.google.com/file/d/1w5UD2EPDiaKSx3W33aj
Rv0olChuXtrQx/view?usp=sharing
Q2: (15 Marks)
A water-LiBr vapor absorption system incorporates a heat exchanger as shown in
the figure. The temperatures of the evaporator, the absorber, the condenser, and the
generator are 10°C, 25°C, 40°C, and 100°C respectively. The strong liquid leaving
the pump is heated to 50°C in the heat exchanger. The refrigerant flow rate through
the condenser is 0.12 kg/s. Calculate (i) the heat rejected in the absorber, and (ii) the
COP of the cycle.
Yo 8
XE-V
lo
9
Pc
7
condenser
5
Qgen
PG
100
Qabs
Pe
evaporator
PRV
6
PA
10
3
generator
heat exchanger
2
pump
185
absorber
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