General, Organic, and Biological Chemistry
General, Organic, and Biological Chemistry
7th Edition
ISBN: 9781285853918
Author: H. Stephen Stoker
Publisher: Cengage Learning
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Chapter 12, Problem 12.96EP

(a)

Interpretation Introduction

Interpretation:

The molecular formula for the given cycloalkane structure has to be found.

Concept Introduction:

Organic compounds are the important basis of life.  They include gasoline, coal, dyes, and clothing fibers etc.  The compounds that are obtained from living organisms are termed as organic compounds and those obtained from the earth are known as inorganic compounds.  Organic compounds are found in earth also apart from living organisms.  All the organic compounds contain the element carbon.  Urea was synthesized in the laboratory which is an organic compound.

Hydrocarbons are the organic compounds that contain only hydrogen and carbon atoms.  Hydrocarbon derivatives are the one in which the compounds contain hydrogen and carbon atoms along with one or more additional elements.  The additional elements that can be present in hydrocarbon derivatives are oxygen, nitrogen, sulphur, chlorine, bromine etc.

Hydrocarbons are further classified into two categories.  They are saturated hydrocarbons and unsaturated hydrocarbons.  The hydrocarbons that contain single bonds between carbon atoms in the entire molecule is known as saturated hydrocarbon.  The hydrocarbons that contain atleast one double or triple bond between two carbon atoms in the entire molecule is known as unsaturated hydrocarbon.

Cycloalkanes are a class of saturated hydrocarbons that contain a ring of carbon atoms with or without alkyl substituents on it.  The general molecular formula for cycloalkanes is CnH2n.  “n” is the number of carbon atoms present.  Some of the basic examples of cycloalkanes are cyclopropane (C3H6), cyclobutane (C4H8).

In a line-angle structural formula of cycloalkanes, the intersection of two lines represent a methylene group (CH2 group).  When substituents are present in the cycloalkane ring, three- and four-way intersections of lines are also possible.  CH group is present when there is a three-way intersection and a carbon atom alone is present when there is a four-way intersection.

(a)

Expert Solution
Check Mark

Answer to Problem 12.96EP

The molecular formula for the given cycloalkane is C5H10.

Explanation of Solution

Given cycloalkane is,

General, Organic, and Biological Chemistry, Chapter 12, Problem 12.96EP , additional homework tip  1

The above structure is a line-angle structural formula representation.  This structure has a total of five intersections.  Therefore, the total number of carbon atoms present in the given structure is found to be five.

The molecular formula for the given cycloalkane can be found using the general molecular formula.  General molecular formula for cycloalkane is CnH2n.  The total number of carbon atoms in the given cycloalkane is 5.  This means “n” is five.  Substitution this is the general molecular formula as shown below, the molecular formula can be obtained.

  CnH2nC5H(2*5)C5H10

The molecular formula for the given cycloalkane is found to be C5H10.

Conclusion

The molecular formula for the given cycloalkane is found out using the general molecular formula for cycloalkanes.

(b)

Interpretation Introduction

Interpretation:

The molecular formula for the given cycloalkane structure has to be found.

Concept Introduction:

Organic compounds are the important basis of life.  They include gasoline, coal, dyes, and clothing fibers etc.  The compounds that are obtained from living organisms are termed as organic compounds and those obtained from the earth are known as inorganic compounds.  Organic compounds are found in earth also apart from living organisms.  All the organic compounds contain the element carbon.  Urea was synthesized in the laboratory which is an organic compound.

Hydrocarbons are the organic compounds that contain only hydrogen and carbon atoms.  Hydrocarbon derivatives are the one in which the compounds contain hydrogen and carbon atoms along with one or more additional elements.  The additional elements that can be present in hydrocarbon derivatives are oxygen, nitrogen, sulphur, chlorine, bromine etc.

Hydrocarbons are further classified into two categories.  They are saturated hydrocarbons and unsaturated hydrocarbons.  The hydrocarbons that contain single bonds between carbon atoms in the entire molecule is known as saturated hydrocarbon.  The hydrocarbons that contain atleast one double or triple bond between two carbon atoms in the entire molecule is known as unsaturated hydrocarbon.

Cycloalkanes are a class of saturated hydrocarbons that contain a ring of carbon atoms with or without alkyl substituents on it.  The general molecular formula for cycloalkanes is CnH2n.  “n” is the number of carbon atoms present.  Some of the basic examples of cycloalkanes are cyclopropane (C3H6), cyclobutane (C4H8).

In a line-angle structural formula of cycloalkanes, the intersection of two lines represent a methylene group (CH2 group).  When substituents are present in the cycloalkane ring, three- and four-way intersections of lines are also possible.  CH group is present when there is a three-way intersection and a carbon atom alone is present when there is a four-way intersection.

(b)

Expert Solution
Check Mark

Answer to Problem 12.96EP

The molecular formula for the given cycloalkane is C8H16.

Explanation of Solution

Given cycloalkane is,

General, Organic, and Biological Chemistry, Chapter 12, Problem 12.96EP , additional homework tip  2

The above structure is a line-angle structural formula representation.  This structure has a total of six intersections and two end lines.  Therefore, the total number of carbon atoms present in the given structure is found to be eight.

The molecular formula for the given cycloalkane can be found using the general molecular formula.  General molecular formula for cycloalkane is CnH2n.  The total number of carbon atoms in the given cycloalkane is 8.  This means “n” is eight.  Substitution this is the general molecular formula as shown below, the molecular formula can be obtained.

  CnH2nC8H(2*8)C8H16

The molecular formula for the given cycloalkane is found to be C8H16.

Conclusion

The molecular formula for the given cycloalkane is found out using the general molecular formula for cycloalkanes.

(c)

Interpretation Introduction

Interpretation:

The molecular formula for the given cycloalkane structure has to be found.

Concept Introduction:

Organic compounds are the important basis of life.  They include gasoline, coal, dyes, and clothing fibers etc.  The compounds that are obtained from living organisms are termed as organic compounds and those obtained from the earth are known as inorganic compounds.  Organic compounds are found in earth also apart from living organisms.  All the organic compounds contain the element carbon.  Urea was synthesized in the laboratory which is an organic compound.

Hydrocarbons are the organic compounds that contain only hydrogen and carbon atoms.  Hydrocarbon derivatives are the one in which the compounds contain hydrogen and carbon atoms along with one or more additional elements.  The additional elements that can be present in hydrocarbon derivatives are oxygen, nitrogen, sulphur, chlorine, bromine etc.

Hydrocarbons are further classified into two categories.  They are saturated hydrocarbons and unsaturated hydrocarbons.  The hydrocarbons that contain single bonds between carbon atoms in the entire molecule is known as saturated hydrocarbon.  The hydrocarbons that contain atleast one double or triple bond between two carbon atoms in the entire molecule is known as unsaturated hydrocarbon.

Cycloalkanes are a class of saturated hydrocarbons that contain a ring of carbon atoms with or without alkyl substituents on it.  The general molecular formula for cycloalkanes is CnH2n.  “n” is the number of carbon atoms present.  Some of the basic examples of cycloalkanes are cyclopropane (C3H6), cyclobutane (C4H8).

In a line-angle structural formula of cycloalkanes, the intersection of two lines represent a methylene group (CH2 group).  When substituents are present in the cycloalkane ring, three- and four-way intersections of lines are also possible.  CH group is present when there is a three-way intersection and a carbon atom alone is present when there is a four-way intersection.

(c)

Expert Solution
Check Mark

Answer to Problem 12.96EP

The molecular formula for the given cycloalkane is C8H16.

Explanation of Solution

Given cycloalkane is,

General, Organic, and Biological Chemistry, Chapter 12, Problem 12.96EP , additional homework tip  3

The above structure is a line-angle structural formula representation.  This structure has a total of six intersections and two end lines.  Therefore, the total number of carbon atoms present in the given structure is found to be eight.

The molecular formula for the given cycloalkane can be found using the general molecular formula.  General molecular formula for cycloalkane is CnH2n.  The total number of carbon atoms in the given cycloalkane is 8.  This means “n” is eight.  Substitution this is the general molecular formula as shown below, the molecular formula can be obtained.

  CnH2nC8H(2*8)C8H16

The molecular formula for the given cycloalkane is found to be C8H16.

Conclusion

The molecular formula for the given cycloalkane is found out using the general molecular formula for cycloalkanes.

(d)

Interpretation Introduction

Interpretation:

The molecular formula for the given cycloalkane structure has to be found.

Concept Introduction:

Organic compounds are the important basis of life.  They include gasoline, coal, dyes, and clothing fibers etc.  The compounds that are obtained from living organisms are termed as organic compounds and those obtained from the earth are known as inorganic compounds.  Organic compounds are found in earth also apart from living organisms.  All the organic compounds contain the element carbon.  Urea was synthesized in the laboratory which is an organic compound.

Hydrocarbons are the organic compounds that contain only hydrogen and carbon atoms.  Hydrocarbon derivatives are the one in which the compounds contain hydrogen and carbon atoms along with one or more additional elements.  The additional elements that can be present in hydrocarbon derivatives are oxygen, nitrogen, sulphur, chlorine, bromine etc.

Hydrocarbons are further classified into two categories.  They are saturated hydrocarbons and unsaturated hydrocarbons.  The hydrocarbons that contain single bonds between carbon atoms in the entire molecule is known as saturated hydrocarbon.  The hydrocarbons that contain atleast one double or triple bond between two carbon atoms in the entire molecule is known as unsaturated hydrocarbon.

Cycloalkanes are a class of saturated hydrocarbons that contain a ring of carbon atoms with or without alkyl substituents on it.  The general molecular formula for cycloalkanes is CnH2n.  “n” is the number of carbon atoms present.  Some of the basic examples of cycloalkanes are cyclopropane (C3H6), cyclobutane (C4H8).

In a line-angle structural formula of cycloalkanes, the intersection of two lines represent a methylene group (CH2 group).  When substituents are present in the cycloalkane ring, three- and four-way intersections of lines are also possible.  CH group is present when there is a three-way intersection and a carbon atom alone is present when there is a four-way intersection.

(d)

Expert Solution
Check Mark

Answer to Problem 12.96EP

The molecular formula for the given cycloalkane is C9H18.

Explanation of Solution

Given cycloalkane is,

General, Organic, and Biological Chemistry, Chapter 12, Problem 12.96EP , additional homework tip  4

The above structure is a line-angle structural formula representation.  This structure has a total of six intersections and three end lines.  Therefore, the total number of carbon atoms present in the given structure is found to be nine.

The molecular formula for the given cycloalkane can be found using the general molecular formula.  General molecular formula for cycloalkane is CnH2n.  The total number of carbon atoms in the given cycloalkane is 9.  This means “n” is nine.  Substitution this is the general molecular formula as shown below, the molecular formula can be obtained.

  CnH2nC9H(2*9)C9H18

The molecular formula for the given cycloalkane is found to be C9H18.

Conclusion

The molecular formula for the given cycloalkane is found out using the general molecular formula for cycloalkanes.

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Chapter 12 Solutions

General, Organic, and Biological Chemistry

Ch. 12.5 - Prob. 2QQCh. 12.5 - Prob. 3QQCh. 12.6 - Prob. 1QQCh. 12.6 - Prob. 2QQCh. 12.6 - Prob. 3QQCh. 12.6 - Prob. 4QQCh. 12.7 - Prob. 1QQCh. 12.7 - Prob. 2QQCh. 12.8 - Prob. 1QQCh. 12.8 - Prob. 2QQCh. 12.8 - Prob. 3QQCh. 12.8 - Prob. 4QQCh. 12.8 - Prob. 5QQCh. 12.8 - Prob. 6QQCh. 12.8 - Prob. 7QQCh. 12.9 - Prob. 1QQCh. 12.9 - Prob. 2QQCh. 12.10 - Prob. 1QQCh. 12.10 - Prob. 2QQCh. 12.11 - Prob. 1QQCh. 12.11 - Prob. 2QQCh. 12.11 - Prob. 3QQCh. 12.12 - Prob. 1QQCh. 12.12 - Prob. 2QQCh. 12.12 - Prob. 3QQCh. 12.13 - Prob. 1QQCh. 12.13 - Prob. 2QQCh. 12.13 - Prob. 3QQCh. 12.14 - Prob. 1QQCh. 12.14 - Prob. 2QQCh. 12.14 - Prob. 3QQCh. 12.15 - Prob. 1QQCh. 12.15 - Prob. 2QQCh. 12.16 - Prob. 1QQCh. 12.16 - Prob. 2QQCh. 12.16 - Prob. 3QQCh. 12.17 - Prob. 1QQCh. 12.17 - Prob. 2QQCh. 12.17 - Prob. 3QQCh. 12.17 - Prob. 4QQCh. 12.18 - Prob. 1QQCh. 12.18 - Prob. 2QQCh. 12.18 - Prob. 3QQCh. 12.18 - Prob. 4QQCh. 12 - Prob. 12.1EPCh. 12 - Prob. 12.2EPCh. 12 - Prob. 12.3EPCh. 12 - Prob. 12.4EPCh. 12 - Indicate whether each of the following situations...Ch. 12 - Indicate whether each of the following situations...Ch. 12 - Prob. 12.7EPCh. 12 - Prob. 12.8EPCh. 12 - What is the difference between a saturated...Ch. 12 - Prob. 12.10EPCh. 12 - Prob. 12.11EPCh. 12 - Prob. 12.12EPCh. 12 - Prob. 12.13EPCh. 12 - Prob. 12.14EPCh. 12 - Prob. 12.15EPCh. 12 - Prob. 12.16EPCh. 12 - Prob. 12.17EPCh. 12 - Prob. 12.18EPCh. 12 - Convert the expanded structural formulas in...Ch. 12 - Prob. 12.20EPCh. 12 - Prob. 12.21EPCh. 12 - Prob. 12.22EPCh. 12 - Prob. 12.23EPCh. 12 - Prob. 12.24EPCh. 12 - Prob. 12.25EPCh. 12 - Prob. 12.26EPCh. 12 - Indicate whether each of the following would be...Ch. 12 - Indicate whether each of the following would be...Ch. 12 - Prob. 12.29EPCh. 12 - Prob. 12.30EPCh. 12 - Prob. 12.31EPCh. 12 - Prob. 12.32EPCh. 12 - Prob. 12.33EPCh. 12 - How many of the numerous seven-carbon alkane...Ch. 12 - Prob. 12.35EPCh. 12 - For each of the following pairs of structures,...Ch. 12 - Prob. 12.37EPCh. 12 - Prob. 12.38EPCh. 12 - Prob. 12.39EPCh. 12 - Prob. 12.40EPCh. 12 - Prob. 12.41EPCh. 12 - What is the name of the IUPAC prefix associated...Ch. 12 - What is the IUPAC name for each of the following...Ch. 12 - What is the IUPAC name for each of the following...Ch. 12 - Prob. 12.45EPCh. 12 - What is the chemical formula for each of the...Ch. 12 - Prob. 12.47EPCh. 12 - Prob. 12.48EPCh. 12 - Prob. 12.49EPCh. 12 - Prob. 12.50EPCh. 12 - Prob. 12.51EPCh. 12 - Prob. 12.52EPCh. 12 - Draw a condensed structural formula for each of...Ch. 12 - Draw a condensed structural formula for each of...Ch. 12 - Prob. 12.55EPCh. 12 - Prob. 12.56EPCh. 12 - Explain why the name given for each of the...Ch. 12 - Prob. 12.58EPCh. 12 - Indicate whether or not the two alkanes in each of...Ch. 12 - Prob. 12.60EPCh. 12 - How many of the 18 C8 alkane constitutional...Ch. 12 - Prob. 12.62EPCh. 12 - Prob. 12.63EPCh. 12 - Prob. 12.64EPCh. 12 - Prob. 12.65EPCh. 12 - Prob. 12.66EPCh. 12 - Do the line-angle structural formulas in each of...Ch. 12 - Do the line-angle structural formulas in each of...Ch. 12 - Convert each of the condensed structural formulas...Ch. 12 - Convert each of the condensed structural formulas...Ch. 12 - Assign an IUPAC name to each of the compounds in...Ch. 12 - Prob. 12.72EPCh. 12 - Prob. 12.73EPCh. 12 - Prob. 12.74EPCh. 12 - For each of the alkane structures in Problem...Ch. 12 - Prob. 12.76EPCh. 12 - Prob. 12.77EPCh. 12 - Prob. 12.78EPCh. 12 - Prob. 12.79EPCh. 12 - Prob. 12.80EPCh. 12 - Prob. 12.81EPCh. 12 - Prob. 12.82EPCh. 12 - Draw condensed structural formulas for the...Ch. 12 - Draw condensed structural formulas for the...Ch. 12 - To which carbon atoms in a hexane molecule can...Ch. 12 - Prob. 12.86EPCh. 12 - Prob. 12.87EPCh. 12 - Prob. 12.88EPCh. 12 - Prob. 12.89EPCh. 12 - Prob. 12.90EPCh. 12 - Prob. 12.91EPCh. 12 - Prob. 12.92EPCh. 12 - Prob. 12.93EPCh. 12 - Using the general formula for a cycloalkane,...Ch. 12 - Prob. 12.95EPCh. 12 - Prob. 12.96EPCh. 12 - Prob. 12.97EPCh. 12 - Prob. 12.98EPCh. 12 - How many secondary carbon atoms are present in...Ch. 12 - Prob. 12.100EPCh. 12 - Prob. 12.101EPCh. 12 - Assign an IUPAC name to each of the following...Ch. 12 - Prob. 12.103EPCh. 12 - What is wrong with each of the following attempts...Ch. 12 - Draw line-angle structural formulas for the...Ch. 12 - Draw line-angle structural formulas for the...Ch. 12 - Prob. 12.107EPCh. 12 - Prob. 12.108EPCh. 12 - Prob. 12.109EPCh. 12 - Prob. 12.110EPCh. 12 - Determine the number of constitutional isomers...Ch. 12 - Determine the number of constitutional isomers...Ch. 12 - Prob. 12.113EPCh. 12 - Determine whether cistrans isomerism is possible...Ch. 12 - Prob. 12.115EPCh. 12 - Prob. 12.116EPCh. 12 - Prob. 12.117EPCh. 12 - Indicate whether the members of each of the...Ch. 12 - Prob. 12.119EPCh. 12 - Prob. 12.120EPCh. 12 - Prob. 12.121EPCh. 12 - Prob. 12.122EPCh. 12 - Which member in each of the following pairs of...Ch. 12 - Prob. 12.124EPCh. 12 - Prob. 12.125EPCh. 12 - Prob. 12.126EPCh. 12 - Answer the following questions about the...Ch. 12 - Prob. 12.128EPCh. 12 - Prob. 12.129EPCh. 12 - Prob. 12.130EPCh. 12 - Prob. 12.131EPCh. 12 - Prob. 12.132EPCh. 12 - Prob. 12.133EPCh. 12 - Write structural formulas for all the possible...Ch. 12 - Assign an IUPAC name to each of the following...Ch. 12 - Assign an IUPAC name to each of the following...Ch. 12 - Prob. 12.137EPCh. 12 - Prob. 12.138EPCh. 12 - Prob. 12.139EPCh. 12 - Draw structural formulas for the following...Ch. 12 - Prob. 12.141EPCh. 12 - Prob. 12.142EPCh. 12 - Prob. 12.143EPCh. 12 - Prob. 12.144EPCh. 12 - Prob. 12.145EPCh. 12 - Prob. 12.146EPCh. 12 - Prob. 12.147EPCh. 12 - Prob. 12.148EP
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