Concept explainers
Interpretation:
The alkane that is gas at room temperature has to be identified from the given set of options.
Concept Introduction:
Organic compounds are represented shortly by the molecular formula and structural formula. Each and every compound has its own molecular formula. Compounds can have same molecular formula but not same structural formula.
Alkanes and cycloalkanes are hydrocarbons. They are nonpolar molecules. Water is a polar molecule. Therefore, alkanes and cycloalkanes do not get solubilized in water. In other words, alkanes and cycloalkanes are insoluble in water.
Regarding density, alkanes and cycloalkanes have density lower than water. When alkanes and cycloalkanes are mixed with water, two layers are formed which is a result of insolubility. Alkanes and cycloalkanes are present on top of water layer which is due to lesser density.
Boiling point of alkanes and cycloalkanes increase with an increase in carbon‑chain length or the ring size. When considering the continuous‑chain alkanes, the boiling point of alkanes increases about
When branching happens in the carbon chain, it lowers the boiling point of alkanes. In simple words, unbranched alkanes have more boiling point than branched alkanes with the same number of carbon atoms.
Cycloalkanes have more boiling point compared to noncyclic alkanes with the same number of carbon atoms. This is due to the more rigid and more symmetrical structures that occur in cyclic systems. Cyclopropane and cyclobutane are gases at room temperature. Cyclopentane to cyclooctane are liquids at room temperature.

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Chapter 1 Solutions
EBK ORGANIC AND BIOLOGICAL CHEMISTRY
- Please help me Please use https://app.molview.com/ to draw this. I tried, but I couldn't figure out how to do it.arrow_forwardPropose a synthesis of 1-butanamine from the following: (a) a chloroalkane of three carbons (b) a chloroalkane of four carbonsarrow_forwardSelect the stronger base from each pair of compounds. (a) H₂CNH₂ or EtzN (b) CI or NH2 NH2 (c) .Q or EtzN (d) or (e) N or (f) H or Harrow_forward
- 4. Provide a clear arrow-pushing mechanism for each of the following reactions. Do not skip proton transfers, do not combine steps, and make sure your arrows are clear enough to be interpreted without ambiguity. a. 2. 1. LDA 3. H3O+ HOarrow_forwardb. H3C CH3 H3O+ ✓ H OHarrow_forward2. Provide reagents/conditions to accomplish the following syntheses. More than one step is required in some cases. a. CH3arrow_forward
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- Organic And Biological ChemistryChemistryISBN:9781305081079Author:STOKER, H. Stephen (howard Stephen)Publisher:Cengage Learning,General, Organic, and Biological ChemistryChemistryISBN:9781285853918Author:H. Stephen StokerPublisher:Cengage Learning

