General, Organic, & Biological Chemistry
General, Organic, & Biological Chemistry
3rd Edition
ISBN: 9780073511245
Author: Janice Gorzynski Smith Dr.
Publisher: McGraw-Hill Education
bartleby

Concept explainers

bartleby

Videos

Question
Book Icon
Chapter 11.6, Problem 11.21P
Interpretation Introduction

(a)

Interpretation:

Whether the following molecule is polar or non-polar should be determined:

General, Organic, & Biological Chemistry, Chapter 11.6, Problem 11.21P , additional homework tip  1

Concept introduction:

Polarity of any individual bond is determined by the electro-negativities of the atoms forming a bond. Any covalent bond is non-polar when two identical atoms or of similar electro-negativity are bonded together. CHandCC bonds are said to be non-polar as their electro-negativities are similar. Bond is said to be polar when two atoms of different electro-negativity are bonded such as bond between carbon atom and hetero-atoms (N,O,halogens) . δ+andδ symbols are given to atoms of less and more electro-negative respectively. Molecule is said to be non-polar if individual bond dipoles cancel in a molecule and if not then the molecule is said to be polar.

Interpretation Introduction

(b)

Interpretation:

Whether the following molecule is polar or non-polar should be determined:

General, Organic, & Biological Chemistry, Chapter 11.6, Problem 11.21P , additional homework tip  2

Concept introduction:

Polarity of any individual bond is determined by the electro-negativities of the atoms forming a bond. Any covalent bond is non-polar when two identical atoms or of similar electro-negativity are bonded together. CHandCC bonds are said to be non-polar as their electro-negativities are similar. Bond is said to be polar when two atoms of different electro-negativity are bonded such as bond between carbon atom and hetero-atoms (N,O,halogens) . δ+andδ symbols are given to atoms of less and more electro-negative respectively. Molecule is said to be non-polar if individual bond dipoles cancel in a molecule and if not then the molecule is said to be polar.

Interpretation Introduction

(c)

Interpretation:

Whether CCl4 is polar or non-polar should be determined:

Concept introduction:

Polarity of any individual bond is determined by the electro-negativities of the atoms forming a bond. Any covalent bond is non-polar when two identical atoms or of similar electro-negativity are bonded together. CHandCC bonds are said to be non-polar as their electro-negativities are similar. Bond is said to be polar when two atoms of different electro-negativity are bonded such as bond between carbon atom and hetero-atoms (N,O,halogens) . δ+andδ symbols are given to atoms of less and more electro-negative respectively. Molecule is said to be non-polar if individual bond dipoles cancel in a molecule and if not then the molecule is said to be polar.

Interpretation Introduction

(d)

Interpretation:

Whether CH3CH2CH2NH2 is polar or non-polar should be determined:

Concept introduction:

Polarity of any individual bond is determined by the electro-negativities of the atoms forming a bond. Any covalent bond is non-polar when two identical atoms or of similar electro-negativity are bonded together. CHandCC bonds are said to be non-polar as their electro-negativities are similar. Bond is said to be polar when two atoms of different electro-negativity are bonded such as bond between carbon atom and hetero-atoms (N,O,halogens) . δ+andδ symbols are given to atoms of less and more electro-negative respectively. Molecule is said to be non-polar if individual bond dipoles cancel in a molecule and if not then the molecule is said to be polar.

Blurred answer
Students have asked these similar questions
Use the symbols δ+ and δ- to indicate the polarity of the highlighted bonds.
Both of the OF2 and CS2 molecules contain polar bonds. Why one of these molecules is polar and the other is nonpolar?
II. Complete the table below. Compound Molecular Geometry Molecule Polarity 1. НCСI 2. H2S 3. CH4 4. N2 Dipole moment of CO2 5. Н2О Take note that bond polarity and molecule polarity are not the same. The presence of polar bonds does not automatically make a molecule polar. The geometry of the molecule also plays an important role. This can be seen in CO2 wherein the electronegativity difference of C and O is 1.0. This equal distribution of polar bonds makes the molecule non- polar.

Chapter 11 Solutions

General, Organic, & Biological Chemistry

Ch. 11.4 - How many H’s are bonded to each indicated carbon...Ch. 11.5 - Prob. 11.12PCh. 11.5 - For each compound: [1] Identify the functional...Ch. 11.5 - Prob. 11.14PCh. 11.5 - Prob. 11.15PCh. 11.5 - Prob. 11.16PCh. 11.5 - Identify all of the functional groups in atenolol,...Ch. 11.5 - Prob. 11.18PCh. 11.5 - Prob. 11.19PCh. 11.6 - Indicate the polar bonds in each compound. Label...Ch. 11.6 - Prob. 11.21PCh. 11.6 - Prob. 11.22PCh. 11.6 - Predict the water solubility of each compound....Ch. 11.6 - Prob. 11.24PCh. 11.7 - Prob. 11.25PCh. 11.7 - Prob. 11.26PCh. 11 - Prob. 11.27PCh. 11 - Prob. 11.28PCh. 11 - Complete each structure by filling in all H’s and...Ch. 11 - Prob. 11.30PCh. 11 - Prob. 11.31PCh. 11 - Prob. 11.32PCh. 11 - Prob. 11.33PCh. 11 - Prob. 11.34PCh. 11 - “Ecstasy” is a widely used illegal stimulant....Ch. 11 - Prob. 11.36PCh. 11 - Explain why each C—C—C bond angle in benzene...Ch. 11 - Prob. 11.38PCh. 11 - Prob. 11.39PCh. 11 - Prob. 11.40PCh. 11 - Convert each compound to a skeletal structure.Ch. 11 - Convert each compound to a skeletal structure.Ch. 11 - Convert each shorthand structure to a complete...Ch. 11 - Convert each shorthand structure to a complete...Ch. 11 - A and B are ball-and-stick models of two compounds...Ch. 11 - Prob. 11.46PCh. 11 - What is wrong in each of the following shorthand...Ch. 11 - Prob. 11.48PCh. 11 - Prob. 11.49PCh. 11 - Albuterol (trade names Proventil and Ventolin) is...Ch. 11 - Prob. 11.51PCh. 11 - Prob. 11.52PCh. 11 - Prob. 11.53PCh. 11 - Prob. 11.54PCh. 11 - Prob. 11.55PCh. 11 - GHB is an addictive, illegal recreational drug...Ch. 11 - Prob. 11.57PCh. 11 - Prob. 11.58PCh. 11 - Prob. 11.59PCh. 11 - Prob. 11.60PCh. 11 - Prob. 11.61PCh. 11 - Prob. 11.62PCh. 11 - You are given two unlabeled bottles of solids, one...Ch. 11 - State how potassium iodide (KI) and pentane...Ch. 11 - The given beaker contains 100 mL of the organic...Ch. 11 - Prob. 11.66PCh. 11 - Why do we need to know the shape of a molecule...Ch. 11 - 1,1-Dichloroethylene (CH2=CCl2) is a starting...Ch. 11 - Indicate the polar bonds in each molecule. Label...Ch. 11 - Indicate the polar bonds in each molecule. Label...Ch. 11 - Classify each molecule as polar or nonpolar.Ch. 11 - Classify each molecule as polar or nonpolar. a....Ch. 11 - Which molecule is more water soluble? Explain.Ch. 11 - Explain why pantothenic acid, vitamin B5, is water...Ch. 11 - Prob. 11.75PCh. 11 - Prob. 11.76PCh. 11 - Explain why regularly taking a large excess of a...Ch. 11 - You can obtain the minimum daily requirement of...Ch. 11 - Prob. 11.79PCh. 11 - Vitamin B6 is obtained by eating a diet that...Ch. 11 - Prob. 11.81PCh. 11 - Can an oxygen-containing organic compound, have...Ch. 11 - Prob. 11.83PCh. 11 - Prob. 11.84PCh. 11 - Benzocaine is the active ingredient in topical...Ch. 11 - Methyl salicylate is responsible for the...Ch. 11 - Answer the following questions about aldosterone,...Ch. 11 - Answer the following questions about...Ch. 11 - Prob. 11.89PCh. 11 - Skin moisturizers come in two types, (a) One type...Ch. 11 - THC is the active component in marijuana (Section...Ch. 11 - Cocaine is a widely abused, addicting drug....
Knowledge Booster
Background pattern image
Chemistry
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Similar questions
SEE MORE QUESTIONS
Recommended textbooks for you
  • Text book image
    Introductory Chemistry: A Foundation
    Chemistry
    ISBN:9781285199030
    Author:Steven S. Zumdahl, Donald J. DeCoste
    Publisher:Cengage Learning
    Text book image
    World of Chemistry, 3rd edition
    Chemistry
    ISBN:9781133109655
    Author:Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCoste
    Publisher:Brooks / Cole / Cengage Learning
    Text book image
    Chemistry & Chemical Reactivity
    Chemistry
    ISBN:9781133949640
    Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
    Publisher:Cengage Learning
  • Text book image
    Chemistry & Chemical Reactivity
    Chemistry
    ISBN:9781337399074
    Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
    Publisher:Cengage Learning
    Text book image
    Chemistry by OpenStax (2015-05-04)
    Chemistry
    ISBN:9781938168390
    Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
    Publisher:OpenStax
    Text book image
    Organic Chemistry
    Chemistry
    ISBN:9781305580350
    Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. Foote
    Publisher:Cengage Learning
Text book image
Introductory Chemistry: A Foundation
Chemistry
ISBN:9781285199030
Author:Steven S. Zumdahl, Donald J. DeCoste
Publisher:Cengage Learning
Text book image
World of Chemistry, 3rd edition
Chemistry
ISBN:9781133109655
Author:Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCoste
Publisher:Brooks / Cole / Cengage Learning
Text book image
Chemistry & Chemical Reactivity
Chemistry
ISBN:9781133949640
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:Cengage Learning
Text book image
Chemistry & Chemical Reactivity
Chemistry
ISBN:9781337399074
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:Cengage Learning
Text book image
Chemistry by OpenStax (2015-05-04)
Chemistry
ISBN:9781938168390
Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Publisher:OpenStax
Text book image
Organic Chemistry
Chemistry
ISBN:9781305580350
Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. Foote
Publisher:Cengage Learning
Types of bonds; Author: Edspira;https://www.youtube.com/watch?v=Jj0V01Arebk;License: Standard YouTube License, CC-BY