Chapter 11.4, Problem 28PPS

To determine

To find: The area of the figure with the given dimension.

Answer to Problem 28PPS

The required area of the region is $5{\text{cm}}^2$ .

Explanation of Solution

Given:

The base of an isosceles triangle has the base of 5 centimetres and the height is of 2 centimetres is removed from the trapezoid that has the base of 6 cm and the second base is of 4cm and the height is of 2 cm.

Calculation:

Consider the area of the isosceles triangle is,

  $\begin{array}{c}A=\frac{1}{2}\left(5\right)\left(2\right)\\ =5{\text{cm}}^2\end{array}$

Then, the area of the trapezoid is,

  $\begin{array}{c}A=\frac{1}{2}\left(a+b\right)\left(h\right)\\ =\frac{1}{2}\left(6+4\right)\left(2\right)\\ =10\end{array}$

Therefore, the required area of the region is,

  $10{\text{cm}}^2-5{\text{cm}}^2=5{\text{cm}}^2$