Chapter 11, Problem 12SGR

To determine

To calculate: The perimeter and area of the given parallelogram

Answer to Problem 12SGR

The perimeter of parallelogram is $38.4{\text{inch}}^{\text{2}}$ and area of parallelogram is $70{\text{inch}}^{\text{2}}$ .

Explanation of Solution

Given information: The two sides of parallelogram are $7\text{inch}$ and $12.2\text{inch}$ , height of the parallelogram is $10\text{inch}$ .

Concept Used:

The perimeter of parallelogram is the sum of all its sides.

So, the perimeter $P$ of the parallelogram which is having two sides $a$ and $b$ is

  $P=2(a+b)$

The area $A$ of the parallelogram which is having base $b$ and height $h$ is

  $A=b\times h$

Calculation:

For perimeter of parallelogram,

In this parallelogram the two sides are $7\text{inch}$ and $12.2\text{inch}$ .

Perimeter of parallelogram is $P=2(a+b)$

Here,

  $a=7\text{inch}$ and $b=12.2\text{inch}$

  $P=2(a+b)$

Substitute the value of $a$ and $b$in $P$formula

  $\begin{array}{l}P=2(7+12.2)\\ \end{array}$

  $P=2(19.2)$

  $P=38.4\text{inch}$

So, perimeter is $38.4\text{inch}$ .

• For area of parallelogram,

In this parallelogram the base is $7\text{inch}$ and height is $10\text{inch}$

Area of parallelogram is $A=b\times h$

Here,

  $b=7\text{inch}$ and $h=10\text{inch}$

  $A=b\times h$

Substitute the value of $b$ and $h$in $A$formula

  $A=7\times 10$

  $A=70{\text{inch}}^{\text{2}}$

So, area is $70{\text{inch}}^{\text{2}}$ .

Conclusion:

The perimeter of parallelogram is $38.4\text{inch}$ and area of parallelogram is $70{\text{inch}}^{\text{2}}$ .