Chapter 11.1, Problem 38HP

To determine

To Find: To discuss the perimeter of rectangular and non-rectangular parallelograms.

Answer to Problem 38HP

The answer is never.

Explanation of Solution

Given information: Given height and area of both the parallelograms are same.

Formula used: Area of parallelogram $=\text{base}\times \text{height}$

Let the height be h and area be A of the given parallelograms.

Thus, base side of first parallelogram is

  $\begin{array}{l}\text{A}=\text{base}\times \text{h}\\ \text{base}=\frac{\text{A}}{\text{h}}\end{array}$

Similarly, the base of second parallelogram is

  $\begin{array}{l}\text{A}=\text{base}\times \text{h}\\ \text{base}=\frac{\text{A}}{\text{h}}\end{array}$

Thus, the base side of both the parallelograms are equal.

So, the perimeter of both the parallelograms are also equal.

Hence, the perimeter of non-rectangle parallelogram is never greater than the perimeter of rectangle.