Chapter 11.1, Problem 11PPS

To determine

To calculate: To find the perimeter and area of parallelogram.

Answer to Problem 11PPS

The Area and Perimeter of parallelogram is $315ft{.}^2$ and $76ft.$ respectively.

Explanation of Solution

Given information: The given figure in the question.

Calculation:

Base of parallelogram = 21 ft.

Now, use Pythagoras theorem to find h of parallelogram

  $\begin{array}{l}{a}^2+b^2=c^2\\ 8^2+h^2={17}^2\\ h^2={17}^2-8^2\\ h^2=289-64\\ h^2=225\\ h=\sqrt{225}\\ h=15ft.\end{array}$

For the area of parallelogram,

  $\begin{array}{c}\text{Area = base }\times \text{ height}\\ =21\times 15\\ =315ft{.}^2\end{array}$

For the perimeter of parallelogram

  $\begin{array}{c}\text{Perimeter = 2}\times \text{( base + height )}\\ =2\times (21+17)\\ =2\times (38)\\ =76ft.\end{array}$