Chapter 11, Problem 16MCQ

To determine

To find: The area of the shaded sector.

Answer to Problem 16MCQ

The area of the sector is $6.20f{t}^2$ .

Explanation of Solution

Given Information: Given radius is $2.1ft$ and angle is ${161}^{\circ }$ .

Given radius is $2.1ft$ and angle is ${161}^{\circ }$ .

Area of sector:

  $\begin{array}{l}=\frac{\theta }{{360}^{\circ }}\pi r^2\\ =\frac{{161}^{\circ }\times 22\times 2.1\times 2.1}{{360}^{\circ }\times 7}\\ =6.20f{t}^2\end{array}$

Thus, the area of the sector is $6.20f{t}^2$ .