Chapter 11.3, Problem 19PPE

To determine

To divide $\left(-4q^2-22q+12\right)÷\left(2q+1\right)$ .

Answer to Problem 19PPE

The quotient for $\left(-4q^2-22q+12\right)÷\left(2q+1\right)$ is $-2q-10$ and remainder is 22

Explanation of Solution

Given:

  $\left(-4q^2-22q+12\right)÷\left(2q+1\right)$

Concept Used:

Steps to follow before applying Long Division method:

1. Write the terms of the dividend and divisor in descending powers of the variable.
2. Insert placeholders with zero coefficients for missing powers of the variable.

Calculation:

To divide $\left(-4q^2-22q+12\right)÷\left(2q+1\right)$ use long division method.

The division may be proceeded as:

  $\begin{array}{l}2q+1)-4q^2-22q+12(-2q-10\\ \underset{\_}{-4q^2-2q}\\ -20q+12\\ \underset{\_}{-20q-10}\\ \underset{\_}{22}\end{array}$

Thus, the quotient for $\left(-4q^2-22q+12\right)÷\left(2q+1\right)$ is $-2q-10$ and remainder is 22.