Chapter 11.3, Problem 1LC

To determine

To divide $\left(20m^3+10m^2-5m-3\right)÷5m^2$ .

Answer to Problem 1LC

The quotient of given division is $4m+2$ and remainder is $-5m-3$ .

Explanation of Solution

Given:

  $\left(20m^3+10m^2-5m-3\right)÷5m^2$

Concept Used:

Steps to follow before applying Long Division method:

1. Write the terms of the dividend and divisor in descending powers of the variable.
2. Insert placeholders with zero coefficients for missing powers of the variable.

Calculation:

To find the quotient for $\left(20m^3+10m^2-5m-3\right)÷5m^2$ use long division method.

First notice that the terms of dividend and divisor are already in descending powers of the variable.

Thus, the division may be proceeded as:

  $\begin{array}{l}5m^2)20m^3+10m^2-5m-3(4m+2\\ \underset{\_}{20m^3}\\ \text{ 10}{m}^2\\ \underset{\_}{10m^2}\\ \underset{\_}{-5m-3}\end{array}$

The quotient of given division is $4m+2$ and remainder is $-5m-3$ .