THERMODYNAMICS (LL)-W/ACCESS >CUSTOM<
9th Edition
ISBN: 9781266657610
Author: CENGEL
Publisher: MCG CUSTOM
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Textbook Question
Chapter 1.11, Problem 121FEP
Consider a fish swimming 5 m below the free surface of water. The increase in the pressure exerted on the fish when it dives to a depth of 25 m below the free surface is
- (a) 196 Pa
- (b) 5400 Pa
- (c) 30,000 Pa
- (d) 196,000 Pa
- (e) 294,000 Pa
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(8) Figure Q8 shows a T cross-section of a T beam which is constructed from three metal plates each having a width of 12 mm and sectional
engths of X=72 mm, Y=65 mm and Z=88 mm, where the plates are used for the web section, and the two flange sections respectively, as
llustrated in Figure Q8.
Calculate the neutral axis of the T-beam cross-section (as measured from the base) in units of millimetres, stating your answer to the
nearest 1 decimal place.
Z mm
Y mm
12 mm
X mm
Figure Q8
12 mm
12 mm
(10) A regular cross-section XXY mm beam, where X-94 m and Y=62 m and 1800 mm long, is loaded from above in the middle with a load of
Z=2 kN causing a compressive Bending Stress at the top of the beam and tensile Bending Stress at the bottom of the beam. The beam in
addition experiences a tensile end loading in order to reduce the compressive stress in the beam to a near zero value. The configuration of the
beam is illustrated in Figure Q10.
Calculate the end loading force required in order to reduce total compressive stress experienced in the beam to be near zero?
State your answer to the nearest 1 decimal place in terms of kilo-Newtons.
Z kN
Y mm
1800 mm
X mm
? KN
Figure Q10
? KN
(12) Figure Q12 shows a framework consisting of 3 upward pointing isosceles triangles and 2 downward pointing isosceles triangles. The
framework is loaded at joint F with a downward force of 20 kN. The applied force causes a vertical reaction force at A and D.
The design of the framework is such that horizontal base of the isosceles triangles form an angle of 30° degrees with the diagonal members.
You are asked to find the internal force in member AE in kilo-Newtons to 1 decimal place (using the standard sign convention given in the
module formula booklet)?
Select the valid option from the list below.
E
F
S
20 kN
RAX = ?? KN
30°
30°
30°
30°
30°
30°
A
H
H
B
D
RAV = ?? KN
Roy = ?? KN
A. The solution to the problem is found to be -20.0 kN.
○ B. The solution to the problem is found to be -10.0 kN.
○ C. The solution to the problem is found to be +11.5 kN.
OD. The solution to the problem is found to be +23.1 kN.
O E. No Valid Answer
Chapter 1 Solutions
THERMODYNAMICS (LL)-W/ACCESS >CUSTOM<
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- (14) An inverted T beam is constructed from a top square cross-section section and a bottom rectangular cross-section of the same length. The cross-section dimensions of the sections are as follows: - Top Square Section 30 mm x 30 mm (width x depth) Bottom Rectangular Section 50 mm x 30 mm Figure Q14 shows the cross-section arrangement of the plates. Given that compression and tension behave the same in terms of stress analysis. Calculate the distance, Ymax, you would use to calculate a safe bending stress value for further analysis. You are required to state your answer in millimetres to the nearest whole number. 30 mm 30 mm O O A. 34 B. 26 O c. 33 D.27 ○ E. No Valid Answer 30 mm 50 mm Figure Q14 1marrow_forward(15) A block of metal with a Young's Modulus of E=200 GPa and Poisson's ratio of 0.3, has dimensions of 38 mm × 20 mm x 80 mm for the lengths X, Y and Z respectively as illustrated in Figure Q15. The block experiences a tensile force in the x-direction of 100 kN and also an applied tensile force in the z-direction of 200 kN as illustrated in Figure Q15. Calculate the strain experienced in the x-direction in terms of micro-strain. Stating your answer to the nearest whole number. 100 kN 200 kN X=38 mm Y = 20 mm ○ A.-188 microstrain OB. -82 microstrain ○ c. no valid answer OD. +83 microstrain ○ E. -187 microstrain Z Figure Q15 200 kN Z = 80 mm 100 kN y Xarrow_forwardFigure Q3 shows a symmetrically loaded beam, loaded with a single Uniform Distributed Load (UDL) starting from the leftmost position A (x = 0 m) ending at the end of the beam at the rightmost position D. The UDL has loading case of 10 kN/m, see Figure Q3 for the start and end positions. There are two symmetrically located pivots causing reaction forces of RB at position B (Y = 1.3 m) and RC at position C. The central section of the beam spans for 2.4 m. Calculate the Shear Force value at a position of X=1.9 m. State your answer in kilo-Newtons to one decimal place.arrow_forward
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