a)
Interpretation: The dissolution of the following in water or hexane has to be predicted.
Concept Introduction:
The bonds involving the atoms with various electronegativites having a large dipole moment are called as polar solvents. Example of polar solvent is Water.
The bonds involving the atoms with same electronegativites are called as non polar solvents. Examples of non polar solvents are Gasoline, Hexane etc
b)
Interpretation: The dissolution of the following in water or hexane has to be predicted.
Concept Introduction:
The bonds involving the atoms with various electronegativites having a large dipole moment are called as polar solvents. Example of polar solvent is Water.
The bonds involving the atoms with same electronegativites are called as non polar solvents. Examples of non polar solvents are Gasoline, Hexane etc
c)
Interpretation: The dissolution of the following in water or hexane has to be predicted.
Concept Introduction:
The bonds involving the atoms with various electronegativites having a large dipole moment are called as polar solvents. Example of polar solvent is Water.
The bonds involving the atoms with same electronegativites are called as non polar solvents. Examples of non polar solvents are Gasoline, Hexane etc
d).
Interpretation: The dissolution of the following in water or hexane has to be predicted.
Concept Introduction:
The bonds involving the atoms with various electronegativites having a large dipole moment are called as polar solvents. Example of polar solvent is Water.
The bonds involving the atoms with same electronegativites are called as non polar solvents. Examples of non polar solvents are Gasoline, Hexane etc
e)
Interpretation: The dissolution of the following in water or hexane has to be predicted.
Concept Introduction:
The bonds involving the atoms with various electronegativites having a large dipole moment are called as polar solvents. Example of polar solvent is Water.
The bonds involving the atoms with same electronegativites are called as non polar solvents. Examples of non polar solvents are Gasoline, Hexane etc
f)
Interpretation: The dissolution of the following in water or hexane has to be predicted.
Concept Introduction:
The bonds involving the atoms with various electronegativites having a large dipole moment are called as polar solvents. Example of polar solvent is Water.
The bonds involving the atoms with same electronegativites are called as non polar solvents. Examples of non polar solvents are Gasoline, Hexane etc
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Chapter 11 Solutions
Chemistry with Access Code, Hybrid Edition
- Concentrated hydrochloric acid contains 1.00 mol HCl dissolved in 3.31 mol H2O. What is the mole fraction of HCl in concentrated hydrochloric acid? What is the molal concentration of HCl?arrow_forwardRefer to Figure 13.10 ( Sec. 13-4b) to answer these questions. (a) Does a saturated solution occur when 65.0 g LiCl is present in 100 g H2O at 40 C? Explain your answer. (b) Consider a solution that contains 95.0 g LiCl in 100 g H2O at 40 C. Is the solution unsaturated, saturated, or supersaturated? Explain your answer. (c) Consider a solution that contains 50. g Li2SO4 in 200. g H2O at 50 C. Is this solution unsaturated, saturated, or supersaturated? Explain your answer. Figure 13.10 Solubility of ionic compounds versus temperature.arrow_forwardYou make a saturated solution of NaCl at 25 C. No solid is present in the beaker holding the solution. What can be done to increase the amount of dissolved NaCl in this solution? (See Figure 13.11.) (a) Add more solid NaCl. (b) Raise the temperature of the solution. (c) Raise the temperature of the solution, and add some NaCl. (d) Lower the temperature of the solution, and add some NaCl. Figure 13.11 The temperature dependence of the solubility of some ionic compounds in wafer. The solubility of most ionic compounds increases with increasing temperature This is illustrated using NH4CI (ports b and c).arrow_forward
- Consider three test tubes. Tube A has pure water. Tube B has an aqueous 1.0 m solution of ethanol, C2H5OH. Tube C has an aqueous 1.0 m solution of NaCl. Which of the following statements are true? (Assume that for these solutions 1.0m=1.0M.) (a) The vapor pressure of the solvent over tube A is greater than the solvent pressure over tube B. (b) The freezing point of the solution in tube B is higher than the freezing point of the solution in tube A. (c) The freezing point of the solution in tube B is higher than the freezing point of the solution in tube C. (d) The boiling point of the solution in tube B is higher than the boiling point of the solution in tube C. (e) The osmotic pressure of the solution in tube B is greater than the osmotic pressure of the solution in tube C.arrow_forwardDimethylglyoxime [DMG, (CH3CNOH)2] is used as a reagent to precipitate nickel ion. Assume that 53.0 g of DMC has been dissolved in 525 g of ethanol (C2H5OH). s The red, insoluble compound formed between nickel(II)ion and dimethylglyoxime (DMG) is precipitated when DMG is added to a bask solution of Ni2+ (aq). (a) What is the mole fraction of DMG? (b) What is the molality of the solution? (c) What is the vapor pressure of the ethanol over the solution at ethanols normal boiling point of 78.4 C? (d) What is the boiling point of the solution? (DMG does not produce ions in solution.) (Kbp for ethanol = +1.22 C/m)arrow_forwardSodium chloride (NaCl) is commonly used to melt ice on roads during the winter. Calcium chloride (CaCl2) is sometimes used for this purpose too. Let us compare the effectiveness of equal masses of these two compounds in lowering the freezing point of water, by calculating the freezing point depression of solutions containing 200. g of each salt in 1.00 kg of water. (An advantage of CaCl2 is that it acts more quickly because it is hygroscopic, that is. it absorbs moisture from the air to give a solution and begin the process. A disadvantage is that this compound is more costly.)arrow_forward
- The following table lists the concentrations of the principal ions in seawater: (a) Calculate the freezing point of seawater. (b) Calculate the osmotic pressure of seawater at 25 C. What is the minimum pressure needed to purify seawater by reverse osmosis?arrow_forwardA compound of manganese, carbon, and oxygen contains 28.17% Mn and 30.80% C. When 0.125 g of this compound is dissolved in 5.38 g of cyclohexane, the solution freezes at 5.28C. What is the molecular formula of this compound?arrow_forwardA sample of water contains 0.010 ppm lead ions, Pb2+. (a) Calculate the mass of lead ions per liter in this solution.(Assume the density of the water solution is 1.0 g/mL.) (b) Calculate the mass fraction of lead in ppb.arrow_forward
- Specifications for lactated Ringers solution, which is used for intravenous (IV) injections, are as follows to reach 100. mL of solution: 285315 mg Na+ 14.117.3 mg K+ 4.9Q.O mg Ca2+ 368408 mg Cl 231261 mg lactate, C3H5O3 a. Specify the amount of NaCl, KCl, CaCl2 2H2O, and NaC3H5O3 needed to prepare 100. mL lactated Ringers solution. b. What is the range of the osmotic pressure of the solution at 37C, given the preceding specifications?arrow_forwardThe dispersed phase of a certain colloidal dispersion consists of spheres of diameter 1.0 102 nm. (a) What are the volume (V=43r2) and surface area (A = r2) of each sphere? (b) How many spheres are required to give a total volume of 1.0 cm3? What is the total surface area of these spheres in square meters?arrow_forwardIn Exercise 96 in Chapter 8, the pressure of CO2 in a bottle of sparkling wine was calculated assuming that the CO2 was insoluble in water. This was a bad assumption. Redo this problem by assuming that CO2 obeys Henry s law. Use the data given in that problem to calculate the partial pressure of CO2 in the gas phase and the solubility of CO2 in the wine at 25C. The Henrys law constant for CO2 is 3.1 w2 mol/L atm at 25C with Henrys law in the form C = kP, where C is the concentration of the gas in mol/L.arrow_forward
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