Chapter 11, Problem 110CWP

Interpretation Introduction

Interpretation: The mass percent, molality, molarity and mole fraction of Cesium chloride has to be calculated.

Concept introduction:

The mass percent can be defined as the mass of solute in grams to the total mass of solute in grams is multiply in $\text{100}$. It can be given by the equation,

$\text{Mass \%=}\frac{\text{Mass}\text{of}\text{solue(in}\text{g)}}{\text{Total}\text{mass}\text{(in g)}}\text{×100}$

Molality of a solution also called as molal concentration can be defined as the mass of solute in grams to the mass of the solvent in kilograms. It can be given by the equation,

$\text{Molality(mol}{\text{kg}}^{\text{-1}}\text{)=}\frac{\text{Mass}\text{of}\text{solue(in}\text{g)}}{\text{Mass}\text{of}\text{solvent(in}\text{kg)}}$

Molarity can be defined as the moles of solute (in grams) to the volume of the solution (in litres). The molarity of a solution can be given by the formula,

$\text{Molarity(M)=}\frac{\text{Moles}\text{of}\text{solute(in}\text{g)}}{\text{Volume}\text{of}\text{solution(in}\text{L)}}$

Mole fraction of a compound can be defined as the number of moles of a substance to the total number of moles present in them. The mole fraction can be calculated by,

$\text{Mole}\text{fraction}\text{of}\text{compound=}\frac{\text{Number}\text{of}\text{moles(in}\text{mol)}}{\text{Total}\text{number}\text{of}\text{moles(in}\text{mol)}}$