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Concept explainers
Interpretation:
The relation between the principle quantum number and distance of an electron from the nucleus needs to be explained.
Concept introduction:
The potential energy of the electron inversely varies with the distance of electron from the nucleus.
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Answer to Problem 27A
The energy level where the electron founds is occurs at a particular distance from the nucleus of the atom is said to be principle energy level.
Explanation of Solution
The electron which is away from the nucleus possess higher potential energy while the electron which is close to the nucleus possess lowest potential energy. So, it conclude that the potential energy is inversely varies with the distance of electron from the nucleus. So, electron in closet orbit is tightly bound to the nucleus as compared to distinct one and the principle energy level is represented by “n”.
When the value of principle energy level is increase then the electrons spends longer distinct from the nucleus.
Chapter 11 Solutions
World of Chemistry, 3rd edition
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- a) 5. Circle all acidic (and anticoplanar to the Leaving group) protons in the following molecules, Solve these elimination reactions, and identify the major and minor products where appropriate: 20 points + NaOCH3 Br (2 productarrow_forwardNonearrow_forwardDr. Mendel asked his BIOL 260 class what their height was and what their parent's heights were. He plotted that data in the graph below to determine if height was a heritable trait. A. Is height a heritable trait? If yes, what is the heritability value? (2 pts) B. If the phenotypic variation is 30, what is the variation due to additive alleles? (2 pts) Offspring Height (Inches) 75 67.5 60 52.5 y = 0.9264x + 4.8519 55 60 65 MidParent Height (Inches) 70 75 12pt v V Paragraph B IUA > AT2 v Varrow_forward
- Experiment: Each team will be provided with 5g of a mixture of acetanilide and salicylic acid. You will divide it into three 1.5 g portions in separate 125 mL Erlenmeyer flasks savıng some for melting point analysis. Dissolve the mixture in each flask in ~60mL of DI water by heating to boiling on a hotplate. Take the flasks off the hotplate once you have a clear solution and let them stand on the bench top for 5 mins and then allow them to cool as described below. Sample A-Let the first sample cool slowly to room temperature by letting it stand on your lab bench, with occasional stirring to promote crystallization. Sample B-Cool the second sample 1n a tap-water bath to 10-15 °C Sample C-Cool the third sample in an ice-bath to 0-2 °C Results: weight after recrystalization and melting point temp. A=0.624g,102-115° B=0.765g, 80-105° C=1.135g, 77-108 What is the percent yield of A,B, and C.arrow_forwardRel. Intensity Q 1. Which one of the following is true of the compound whose mass spectrum is shown here? Explain how you decided. 100 a) It contains chlorine. b) It contains bromine. c) It contains neither chlorine nor bromine. 80- 60- 40- 20- 0.0 0.0 TT 40 80 120 160 m/z 2. Using the Table of IR Absorptions how could you distinguish between these two compounds in the IR? What absorbance would one compound have that the other compound does not? HO CIarrow_forwardIllustrate reaction mechanisms of alkenes with water in the presence of H2SO4, detailing each step of the process. Please show steps of processing. Please do both, I will thumb up for sure #1 #3arrow_forward
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