Essentials of Materials Science and Engineering, SI Edition
4th Edition
ISBN: 9781337672078
Author: ASKELAND, Donald R., WRIGHT, Wendelin J.
Publisher: Cengage Learning
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Chapter 11, Problem 11.4P
Interpretation Introduction
Interpretation:
For high temperature applications, the major problems associated with utilization of intermetallics needs to be explained.
Concept Introduction:
The intermetallic compound is a substance that comprises a minimum of two metallic constituents that blend to give a new phase of the same properties and other features that is consisted of a parent material. It also consists of one or more than one non-metallic element if required.
- The intermetallic compounds are very hard and brittle in nature.
- They hold properties like strength and ductility.
- They could withstand at high temperatures.
- The
mechanical properties are equivalent to that of ceramics. - They also hold magnetic properties.
- They are good conductors as well.
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I need help in creating a matlab code to find the currents
The beam shown in the figure below is a W16 × 31 of A992 steel and has continuous lateral support.
The two concentrated loads are service live loads. Neglect the weight of the beam and determine
whether the beam is adequate. Suppose that P = 52 k.
For W16 × 31: d = 15.9 in., tw
=
0.275 in., h/tw = 51.6,
and M = M₁ = 203 ft-kip, Mn/₁ = Mp/α = 135 ft-kip.
P
Р
W16 x 31
a. Use LRFD.
Calculate the required moment strength, the allowable shear strength, and the maximum shear.
(Express your answers to three significant figures.)
Mu
=
OvVn
=
ft-kip
kips
kips
Vu =
Beam is -Select-
b. Use ASD.
Calculate the required moment strength, the allowable shear strength, and the maximum shear.
(Express your answers to three significant figures.)
Ma =
Vn/b
-
Va =
Beam is -Select-
ft-kip
kips
kips
Determine the smallest value of yield stress Fy, for which a W-, M-, or S-shape from the list below will
become slender.
bf/2tfh/tw
Shape
W12 × 72
8.99
22.6
W12 × 26
8.54
47.2
M4 × 6
11.9
22.0
M12 x 11.8
6.81
62.5
M6 × 4.4
5.39
47.0
S24 × 80
4.02
41.4
S10 × 35
5.03
13.4
(Express your answer to three significant figures.)
Fy
=
ksi
To which shape does this value apply?
-Select-
✓
Chapter 11 Solutions
Essentials of Materials Science and Engineering, SI Edition
Ch. 11 - Prob. 11.1PCh. 11 - Prob. 11.2PCh. 11 - Prob. 11.3PCh. 11 - Prob. 11.4PCh. 11 - Prob. 11.5PCh. 11 - Prob. 11.6PCh. 11 - Prob. 11.7PCh. 11 - Prob. 11.8PCh. 11 - Prob. 11.9PCh. 11 - Prob. 11.10P
Ch. 11 - Prob. 11.11PCh. 11 - Prob. 11.12PCh. 11 - Prob. 11.13PCh. 11 - Prob. 11.14PCh. 11 - Prob. 11.15PCh. 11 - Prob. 11.16PCh. 11 - Prob. 11.17PCh. 11 - Prob. 11.18PCh. 11 - Prob. 11.19PCh. 11 - Prob. 11.20PCh. 11 - Prob. 11.21PCh. 11 - Prob. 11.22PCh. 11 - Prob. 11.23PCh. 11 - Prob. 11.24PCh. 11 - Prob. 11.25PCh. 11 - Prob. 11.26PCh. 11 - Prob. 11.27PCh. 11 - Prob. 11.28PCh. 11 - Prob. 11.29PCh. 11 - Prob. 11.30PCh. 11 - Prob. 11.31PCh. 11 - Prob. 11.32PCh. 11 - Prob. 11.33PCh. 11 - Prob. 11.34PCh. 11 - Prob. 11.35PCh. 11 - Prob. 11.36PCh. 11 - Prob. 11.37PCh. 11 - Prob. 11.38PCh. 11 - Prob. 11.39PCh. 11 - Prob. 11.40PCh. 11 - Prob. 11.41PCh. 11 - Prob. 11.42PCh. 11 - Prob. 11.43PCh. 11 - Prob. 11.44PCh. 11 - Prob. 11.45PCh. 11 - Prob. 11.46PCh. 11 - Prob. 11.47PCh. 11 - Prob. 11.48PCh. 11 - Prob. 11.49PCh. 11 - Prob. 11.50PCh. 11 - Prob. 11.51PCh. 11 - Prob. 11.52PCh. 11 - Prob. 11.53DPCh. 11 - Prob. 11.54DPCh. 11 - Prob. 11.55DPCh. 11 - Prob. 11.56CPCh. 11 - Prob. K11.1KP
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