Concept explainers
To find: The mistake done in calculating the number of different outfit combinations and the correct answer.
Answer to Problem 19HP
The total number of outfits is calculated by multiplying the numbers, not by adding them. The correct number of outfits is 80.
Explanation of Solution
Given: There are 4 pairs of shoes, 4 pairs of pants and 5 shirts to choose from.
Concepts Used: Consider m number of distinct items that can be matched up with another set containingn distinct items. Then the first item from the first group can be matched with any one of the n number of items in the second group which gives a total of n combinations. Similarly, for the second item in the first group there are n different combinations and so on. Hence the total number of combinations for mitemswith n itemswill be
= n+ n +n +n + … (m times) =
Calculations: Let’s first find the combinations of clothes from the given number of shirts and pants. Then each outfit combination can be matched with a distinct shoe pair to give the total number of outfit combinations.
There are 4 pairs of pants and 5 shirts. Total combination of outfits if chosen from the shirt and pants is =
These 20 combinations of outfits can then be matched with any one of the 4 pairs of shoes. Thus, total possible combination of outfits of shirts, pant and shoes is
=
The mistake was that the numbers were added whereas they should have been multiplied.
Chapter 10 Solutions
Glencoe Math Accelerated, Student Edition
Additional Math Textbook Solutions
Calculus: Early Transcendentals (2nd Edition)
Elementary Statistics (13th Edition)
A Problem Solving Approach To Mathematics For Elementary School Teachers (13th Edition)
Introductory Statistics
Basic Business Statistics, Student Value Edition
Elementary Statistics: Picturing the World (7th Edition)
- 1. Show that the vector field F(x, y, z) = (2x sin ye³)ix² cos yj + (3xe³ +5)k satisfies the necessary conditions for a conservative vector field, and find a potential function for F.arrow_forward1. Newton's Law of Gravitation (an example of an inverse square law) states that the magnitude of the gravitational force between two objects with masses m and M is |F| mMG |r|2 where r is the distance between the objects, and G is the gravitational constant. Assume that the object with mass M is located at the origin in R³. Then, the gravitational force field acting on the object at the point r = (x, y, z) is given by F(x, y, z) = mMG r3 r. mMG mMG Show that the scalar vector field f(x, y, z) = = is a potential function for r √√x² + y² . Fi.e. show that F = Vf. Remark: f is the negative of the physical potential energy, because F = -V(-ƒ).arrow_forward2. Suppose f(x) = 3x² - 5x. Show all your work for the problems below.arrow_forward
- write it down for better understanding pleasearrow_forward1. Suppose F(t) gives the temperature in degrees Fahrenheit t minutes after 1pm. With a complete sentence, interpret the equation F(10) 68. (Remember this means explaining the meaning of the equation without using any mathy vocabulary!) Include units. (3 points) =arrow_forward2. Suppose f(x) = 3x² - 5x. Show all your work for the problems below. a. Evaluate f(-3). If you have multiple steps, be sure to connect your expressions with EQUALS SIGNS. (3 points)arrow_forward
- 4c Consider the function f(x) = 10x + 4x5 - 4x³- 1. Enter the general antiderivative of f(x)arrow_forwardA tank contains 60 kg of salt and 2000 L of water. Pure water enters a tank at the rate 8 L/min. The solution is mixed and drains from the tank at the rate 11 L/min. Let y be the number of kg of salt in the tank after t minutes. The differential equation for this situation would be: dy dt y(0) =arrow_forwardSolve the initial value problem: y= 0.05y + 5 y(0) = 100 y(t) =arrow_forward
- y=f'(x) 1 8 The function f is defined on the closed interval [0,8]. The graph of its derivative f' is shown above. How many relative minima are there for f(x)? O 2 6 4 00arrow_forward60! 5!.7!.15!.33!arrow_forward• • Let > be a potential for the vector field F = (−2 y³, −6 xy² − 4 z³, −12 yz² + 4 2). Then the value of sin((-1.63, 2.06, 0.57) – (0,0,0)) is - 0.336 -0.931 -0.587 0.440 0.902 0.607 -0.609 0.146arrow_forward
- Calculus: Early TranscendentalsCalculusISBN:9781285741550Author:James StewartPublisher:Cengage LearningThomas' Calculus (14th Edition)CalculusISBN:9780134438986Author:Joel R. Hass, Christopher E. Heil, Maurice D. WeirPublisher:PEARSONCalculus: Early Transcendentals (3rd Edition)CalculusISBN:9780134763644Author:William L. Briggs, Lyle Cochran, Bernard Gillett, Eric SchulzPublisher:PEARSON
- Calculus: Early TranscendentalsCalculusISBN:9781319050740Author:Jon Rogawski, Colin Adams, Robert FranzosaPublisher:W. H. FreemanCalculus: Early Transcendental FunctionsCalculusISBN:9781337552516Author:Ron Larson, Bruce H. EdwardsPublisher:Cengage Learning