Chapter 10.6, Problem 3GP

To determine

To calculate: the probability of the outcome of spinner and describe the likelihood.

Answer to Problem 3GP

Probability of getting number greater than 6 that is $P\left(\text{greater}\text{than}\text{6}\right)=\underset{\_}{\frac{2}{5}}$ and event is unlikely to occur.

Explanation of Solution

Given information:

1. Spinner is spun once.
2. Spinner is divided into 10 equal sectors
3. Need to determine the outcome of getting number greater than 6.
4. Associated figure is as follows

  

Formula Used:

  $\text{probablity}\text{of}\text{an}\text{event=}\frac{\text{number}\text{of}\text{favorable}\text{outcomes}}{\text{number}\text{of}\text{possible}\text{outcomes}}$

Calculation:

Number of possible outcomes of spinner $=10$

Need to determine probability of getting number greater than 6 that is $P\left(\text{greater}\text{than}\text{6}\right)$ .

As favorable outcomes are numbers greater than 6 that are 7 , 8 , 9 and 10 , number of favorable out come = 4

Using formula $\text{probablity}\text{of}\text{an}\text{event=}\frac{\text{number}\text{of}\text{favorable}\text{outcomes}}{\text{number}\text{of}\text{possible}\text{outcomes}}$

  $P\left(\text{greater}\text{than}\text{6}\right)=\frac{4}{10}=\frac{2}{5}$

As $\frac{2}{5}$ is equal to $40\%$ , the event of getting number greater than 6 is unlikely to happen .

Hence probability of getting number greater than 6 that is $P\left(\text{greater}\text{than}\text{6}\right)=\underset{\_}{\frac{2}{5}}$ and event is unlikely to occur.