Chapter 10, Problem 23CR

To determine

To find: $\text{the experiment probability that a student chose burger}$.

Answer to Problem 23CR

  $\text{probability=}\frac{31}{100}=31\%$

Explanation of Solution

Given information:

  $\begin{array}{l}\text{Given in a survey of randomly selected students,students chose their preference}\\ \text{from among three meal options for a school event}\text{. }\end{array}$

Calculation:

  $\begin{array}{l}\text{Total students=47+31+22=100}\\ \text{Number of students who chose burger=31}\\ \text{Probability (burger)=}\frac{31}{100}\\ \text{In percentage=31\%}\end{array}$